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Anonymous
Not applicable

Create a pie chart for line items with multiple tags (binary in nature 1,0)

I have a dataset which looks like this.

Item No.Category ACategory BValue
111110$1000
222211$2000
33301$3000
444411$2000

I want to create a pie chart which populates the values of both category A and B. 

 

@ValtteriN 

1 ACCEPTED SOLUTION
Anonymous
Not applicable

Hi  @Anonymous ,

Here are the steps you can follow:

1. Create calculated table.

Table 2 =
SUMMARIZE('Table','Table'[Item No.],
"CategoryA 1",CALCULATE(SUM('Table'[Value]),FILTER(ALL('Table'),'Table'[Category A]=1)),
"CategoryA 0",CALCULATE(SUM('Table'[Value]),FILTER(ALL('Table'),'Table'[Category A]=0)),
"CategoryB 1",CALCULATE(SUM('Table'[Value]),FILTER(ALL('Table'),'Table'[Category B]=1)),
"CategoryB 0",CALCULATE(SUM('Table'[Value]),FILTER(ALL('Table'),'Table'[Category B]=0))
)

vyangliumsft_0-1650007229702.png

2. Result:

All set to Max.

vyangliumsft_1-1650007229707.png

Please click here for the pbix file

 

 

Best Regards,

Liu Yang

If this post helps, then please consider Accept it as the solution to help the other members find it more quickly

View solution in original post

3 REPLIES 3
Anonymous
Not applicable

Hi  @Anonymous ,

Here are the steps you can follow:

1. Create calculated table.

Table 2 =
SUMMARIZE('Table','Table'[Item No.],
"CategoryA 1",CALCULATE(SUM('Table'[Value]),FILTER(ALL('Table'),'Table'[Category A]=1)),
"CategoryA 0",CALCULATE(SUM('Table'[Value]),FILTER(ALL('Table'),'Table'[Category A]=0)),
"CategoryB 1",CALCULATE(SUM('Table'[Value]),FILTER(ALL('Table'),'Table'[Category B]=1)),
"CategoryB 0",CALCULATE(SUM('Table'[Value]),FILTER(ALL('Table'),'Table'[Category B]=0))
)

vyangliumsft_0-1650007229702.png

2. Result:

All set to Max.

vyangliumsft_1-1650007229707.png

Please click here for the pbix file

 

 

Best Regards,

Liu Yang

If this post helps, then please consider Accept it as the solution to help the other members find it more quickly

ValtteriN
Super User
Super User

Hi @Anonymous ,

Like Amit mentioned you should look into unpivoting the data into a format where you have a category column describing if a row belong to A or B category then use the binary data as the value.





Did I answer your question? Mark my post as a solution!

Proud to be a Super User!




amitchandak
Super User
Super User

@Anonymous , What will the legend.

If you have two measures category A and Category B, then you can have pie on that without legend.

 

You can unpivot Category A and Category B use the new column as Legend, the 1/0 column as details and value as value

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