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JamesMF1982
Frequent Visitor

Counting number of times a datediff is over 30

Hi all,

 

I have a current measure which works out the number of days since an enquiry was entered into the system and today

CRM_OpenEnq_DaysSinceEnqLead = calculate(SUMX(ENQUIRYDETAILS,Datediff(ENQUIRYDETAILS[EnquiryBecameLeadDate],Today(),Day)),ENQUIRYDETAILS[EnquiryCurrentStageID] IN {0,1,2})

 

This is working on a table however, I want to have a Card that has the number of times that the results are over 30 days. 

 

Any help on this would be appreciated. 

 

James

1 ACCEPTED SOLUTION
amitchandak
Super User
Super User

@JamesMF1982 , Try like

 

CRM_OpenEnq_DaysSinceEnqLead = calculate(Countrows(Filter(ENQUIRYDETAILS,Datediff(ENQUIRYDETAILS[EnquiryBecameLeadDate],Today(),Day)>30)),ENQUIRYDETAILS[EnquiryCurrentStageID] IN {0,1,2})

View solution in original post

3 REPLIES 3
v-zhangti
Community Support
Community Support

Hi, @JamesMF1982 

 

Can you provide sample data for testing? Sensitive information can be removed in advance. What kind of expected results do you expect? You can also show it with pictures. I look forward to your response.

Best Regards,

Community Support Team _Charlotte

If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.

 

ppm1
Solution Sage
Solution Sage

Please try this expression. I switched to using INT instead of DATEDIFF as it is more performant (especially since an IF would have been needed). The INT returns 1 or 0 for the T/F inside, so only the ones with >30 are counted.

 

Rows Over 30 =
CALCULATE (
    SUMX (
        ENQUIRYDETAILS,
        INT ( ( TODAY () - ENQUIRYDETAILS[EnquiryBecameLeadDate] ) > 30 )
    ),
    ENQUIRYDETAILS[EnquiryCurrentStageID] IN { 0, 1, 2 }
)

 

Pat

Microsoft Employee
amitchandak
Super User
Super User

@JamesMF1982 , Try like

 

CRM_OpenEnq_DaysSinceEnqLead = calculate(Countrows(Filter(ENQUIRYDETAILS,Datediff(ENQUIRYDETAILS[EnquiryBecameLeadDate],Today(),Day)>30)),ENQUIRYDETAILS[EnquiryCurrentStageID] IN {0,1,2})

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