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Frequent Visitor

## Count value in a column and break by a value and count again like a loop

I have a sample like this table. The column count of 2 is the output I expect. With the same ID, order Date ascending. We count number 2 (or rank) by Date. If the value in column A is 1, we break the loop and count (or rank) the number 2 again from the beginning.

Plz help me. Thank you

1 ACCEPTED SOLUTION
Community Support

Hi Phuonghm22,

(1) Create a calculated column to count

``````Co2 =
VAR _date =
CALCULATE (
MAX ( 'Table'[Date] ),
FILTER (
ALL ( 'Table' ),
'Table'[A] <> 2
&& 'Table'[Date] <= EARLIER ( 'Table'[Date] )
&& 'Table'[ID] = EARLIER ( 'Table'[ID] )
)
)
VAR _count =
CALCULATE (
COUNTROWS ( 'Table' ),
FILTER (
ALL ( 'Table' ),
'Table'[Date] <= EARLIER ( 'Table'[Date] )
&& 'Table'[Date] > _date
&& 'Table'[ID] = EARLIER ( 'Table'[ID] )
)
) + 0
RETURN
_count
``````

(2) Final output

Best Regards,

Gallen Luo

If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.

3 REPLIES 3
Community Support

Hi Phuonghm22,

(1) Create a calculated column to count

``````Co2 =
VAR _date =
CALCULATE (
MAX ( 'Table'[Date] ),
FILTER (
ALL ( 'Table' ),
'Table'[A] <> 2
&& 'Table'[Date] <= EARLIER ( 'Table'[Date] )
&& 'Table'[ID] = EARLIER ( 'Table'[ID] )
)
)
VAR _count =
CALCULATE (
COUNTROWS ( 'Table' ),
FILTER (
ALL ( 'Table' ),
'Table'[Date] <= EARLIER ( 'Table'[Date] )
&& 'Table'[Date] > _date
&& 'Table'[ID] = EARLIER ( 'Table'[ID] )
)
) + 0
RETURN
_count
``````

(2) Final output

Best Regards,

Gallen Luo

If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.

Frequent Visitor

Thank you so much

Super User

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