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Phuonghm22
Frequent Visitor

Count value in a column and break by a value and count again like a loop

I have a sample like this table. The column count of 2 is the output I expect. With the same ID, order Date ascending. We count number 2 (or rank) by Date. If the value in column A is 1, we break the loop and count (or rank) the number 2 again from the beginning.

Plz help me. Thank youScreenshot_1.png

1 ACCEPTED SOLUTION
v-jialluo-msft
Community Support
Community Support

Hi Phuonghm22,

 

Please follow these steps:

(1) Create a calculated column to count

 

Co2 =
VAR _date =
    CALCULATE (
        MAX ( 'Table'[Date] ),
        FILTER (
            ALL ( 'Table' ),
            'Table'[A] <> 2
                && 'Table'[Date] <= EARLIER ( 'Table'[Date] )
                && 'Table'[ID] = EARLIER ( 'Table'[ID] )
        )
    )
VAR _count =
    CALCULATE (
        COUNTROWS ( 'Table' ),
        FILTER (
            ALL ( 'Table' ),
            'Table'[Date] <= EARLIER ( 'Table'[Date] )
                && 'Table'[Date] > _date
                && 'Table'[ID] = EARLIER ( 'Table'[ID] )
        )
    ) + 0
RETURN
    _count

vjialluomsft_0-1667289690085.png

 

 

(2) Final output

vjialluomsft_0-1667289581409.png

 

 

Best Regards,

Gallen Luo

If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.

View solution in original post

3 REPLIES 3
v-jialluo-msft
Community Support
Community Support

Hi Phuonghm22,

 

Please follow these steps:

(1) Create a calculated column to count

 

Co2 =
VAR _date =
    CALCULATE (
        MAX ( 'Table'[Date] ),
        FILTER (
            ALL ( 'Table' ),
            'Table'[A] <> 2
                && 'Table'[Date] <= EARLIER ( 'Table'[Date] )
                && 'Table'[ID] = EARLIER ( 'Table'[ID] )
        )
    )
VAR _count =
    CALCULATE (
        COUNTROWS ( 'Table' ),
        FILTER (
            ALL ( 'Table' ),
            'Table'[Date] <= EARLIER ( 'Table'[Date] )
                && 'Table'[Date] > _date
                && 'Table'[ID] = EARLIER ( 'Table'[ID] )
        )
    ) + 0
RETURN
    _count

vjialluomsft_0-1667289690085.png

 

 

(2) Final output

vjialluomsft_0-1667289581409.png

 

 

Best Regards,

Gallen Luo

If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.

Thank you so much

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