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CarsteFoRd
Regular Visitor

Count the number of occurences contained in another columns strings

Hi all 

I am trying to make a new column that count the number of occurences contained in another columns strings

 

My data looks like this (the desired result is marked in yellow)

CarsteFoRd_1-1708612912294.png

 

Thanks in advance 
The Best Carsten 

1 ACCEPTED SOLUTION
Jihwan_Kim
Super User
Super User

Hi,

Please check the below picture and the attached pbix file.

 

Jihwan_Kim_0-1708622119235.png

 

expected result CC =
VAR _maxnumber =
    MAXX (
        ADDCOLUMNS (
            Data,
            "@countdelimiter", LEN ( Data[Path] ) - LEN ( SUBSTITUTE ( Data[Path], "|", "" ) )
        ),
        [@countdelimiter]
    ) + 1
VAR _generateseriestable =
    SELECTCOLUMNS ( GENERATESERIES ( 1, _maxnumber, 1 ), "@number", [Value] )
VAR _t =
    GENERATE (
        _generateseriestable,
        ADDCOLUMNS ( Data, "@item", PATHITEM ( Data[Path], [@number] ) )
    )
RETURN
    COUNTROWS ( FILTER ( _t, [@item] = EARLIER ( Data[ItemID] ) ) )

 


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View solution in original post

2 REPLIES 2
CarsteFoRd
Regular Visitor

Thanks 🙂 

Jihwan_Kim
Super User
Super User

Hi,

Please check the below picture and the attached pbix file.

 

Jihwan_Kim_0-1708622119235.png

 

expected result CC =
VAR _maxnumber =
    MAXX (
        ADDCOLUMNS (
            Data,
            "@countdelimiter", LEN ( Data[Path] ) - LEN ( SUBSTITUTE ( Data[Path], "|", "" ) )
        ),
        [@countdelimiter]
    ) + 1
VAR _generateseriestable =
    SELECTCOLUMNS ( GENERATESERIES ( 1, _maxnumber, 1 ), "@number", [Value] )
VAR _t =
    GENERATE (
        _generateseriestable,
        ADDCOLUMNS ( Data, "@item", PATHITEM ( Data[Path], [@number] ) )
    )
RETURN
    COUNTROWS ( FILTER ( _t, [@item] = EARLIER ( Data[ItemID] ) ) )

 


If this post helps, then please consider accepting it as the solution to help other members find it faster, and give a big thumbs up.


Click here to visit my LinkedIn page

Click here to schedule a short Teams meeting to discuss your question.

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