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I have a clustered column chart and I am wondering if it's possible to show the difference between Delivered and Count All in red (see week number 27).
Solved! Go to Solution.
Hi @Brianii ,
Sorry, Power BI can't implement this feature for the time being, in the Clustered column chart, the colors in the column can only be the same color, and you can't add a color
You can also submit an idea for it at https://ideas.powerbi.com/forums and wait for users with the same needs as you to vote for you to help make it happen as soon as possible.
You can add a category in [Group] to act as a Difference and display it in Visual.
Here are the steps you can follow:
1. Create calculated table.
Table 2 =
var _table1=
SUMMARIZE(
'Table','Table'[Index],
"Group","Difference",
"Value",
SUMX(FILTER(ALL('Table'),'Table'[Index]=EARLIER('Table'[Index])&&'Table'[Group]="Coun_All"),[Value])
- SUMX(FILTER(ALL('Table'),'Table'[Index]=EARLIER('Table'[Index])&&'Table'[Group]="Delivered"),[Value]))
return
UNION(
'Table',_table1)
2. Result:
Best Regards,
Liu Yang
If this post helps, then please consider Accept it as the solution to help the other members find it more quickly
Hi
Thank you for taking your time to respond. Whilst it's not what I am looking for, it's the close. I'll accept this as a solution and submit the idea. Thanks
Hi @Brianii ,
Sorry, Power BI can't implement this feature for the time being, in the Clustered column chart, the colors in the column can only be the same color, and you can't add a color
You can also submit an idea for it at https://ideas.powerbi.com/forums and wait for users with the same needs as you to vote for you to help make it happen as soon as possible.
You can add a category in [Group] to act as a Difference and display it in Visual.
Here are the steps you can follow:
1. Create calculated table.
Table 2 =
var _table1=
SUMMARIZE(
'Table','Table'[Index],
"Group","Difference",
"Value",
SUMX(FILTER(ALL('Table'),'Table'[Index]=EARLIER('Table'[Index])&&'Table'[Group]="Coun_All"),[Value])
- SUMX(FILTER(ALL('Table'),'Table'[Index]=EARLIER('Table'[Index])&&'Table'[Group]="Delivered"),[Value]))
return
UNION(
'Table',_table1)
2. Result:
Best Regards,
Liu Yang
If this post helps, then please consider Accept it as the solution to help the other members find it more quickly
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