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Anonymous
Not applicable

Chart values based on rank

Hello Everyone,

I have following dataset:

ChartRank_DS.JPG

Based on that i want to have 3 charts:

1. Chart #1 is to show items order by sold quantity (pieces)

2. Chart #2 and #3 are to show sales of top 1 sold item by shop (#2 chart) and top 2 sold item by shop (#3)

 

Chart #1 looks like this:
ChartRank chart1.JPG

Chart #2 should look like this:
ChartRank chart2.JPG

I have written following measure:

Rank of Sold Items = 
CALCULATE(
    MAX(Sheet2[Item]),
    FILTER(
        VALUES(Sheet2[Item]),
        RANKX(
            ALL(Sheet2[Item]),
            SUM(Sheet2[Sold pieces])
        ) = 1
    )
)

but this returns Item #4 that is not ranked as #1. I assume that i should use different function then MAX to return name of top 1 ranked item. 
Could you please help change measure so it returns #1 ranked item?

1 ACCEPTED SOLUTION
Jihwan_Kim
Super User
Super User

Hi,

I am not sure if I understood your question correctly, but please try the below whether it suits your requirement.

 

Rank of Sold Items =
CALCULATE (
    MAX ( Sheet2[Item] ),
    FILTER (
        VALUES ( Sheet2[Item] ),
        RANKX ( ALL ( Sheet2[Item] ), CALCULATE ( SUM ( Sheet2[Sold pieces] ) ) ) = 1
    )
)

If this post helps, then please consider accepting it as the solution to help other members find it faster, and give a big thumbs up.


Click here to visit my LinkedIn page

Click here to schedule a short Teams meeting to discuss your question.

View solution in original post

2 REPLIES 2
Jihwan_Kim
Super User
Super User

Hi,

I am not sure if I understood your question correctly, but please try the below whether it suits your requirement.

 

Rank of Sold Items =
CALCULATE (
    MAX ( Sheet2[Item] ),
    FILTER (
        VALUES ( Sheet2[Item] ),
        RANKX ( ALL ( Sheet2[Item] ), CALCULATE ( SUM ( Sheet2[Sold pieces] ) ) ) = 1
    )
)

If this post helps, then please consider accepting it as the solution to help other members find it faster, and give a big thumbs up.


Click here to visit my LinkedIn page

Click here to schedule a short Teams meeting to discuss your question.
Anonymous
Not applicable

Thank You!

It seems that you did understood because it works. 

 

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