cancel
Showing results for
Did you mean:  Helper III

## Can anybody help me implement this logic in DAX? We are using direct query.

x, y, z are three different fields/columns with values x1, x2...; y1, y2...; and so on.

in case of x we just know "x1" and we need to find x2, x3, x4... in following manner:
x2= x1+y1-z1
x3= x2+y2-z2
and so on

all y and z field values are given but in case of x we just know x1.

How can we apply this in Dax to find x2, x3,....?

1 ACCEPTED SOLUTION  Super User

Hi @shivam

i assume that you have a unique date or index column. Otherwise you nee to create one.

``````X =
VAR X1 = 1 --inset the initial value
VAR CurrentIndex = TablName[Index]
VAR TableBefore =
FILTER ( TablName, TablName[Index] < CurrentIndex )
VAR Y =
SUMX ( TableBefore, TablName[Y] )
VAR Z =
SUMX ( TableBefore, TablName[Z] )
RETURN
X1 + Y - Z``````

5 REPLIES 5  Helper III

x, y, z are three different fields/columns with values x1, x2...; y1, y2...; and so on.

in case of x we just know "x1" and we need to find x2, x3, x4... in following manner:
x2= x1+y1-z1
x3= x2+y2-z2
and so on

all y and z field values are given but in case of x we just know x1.

How can we apply this in Dax to find x2, x3,....?  Super User  Super User

Hi @shivam

i assume that you have a unique date or index column. Otherwise you nee to create one.

``````X =
VAR X1 = 1 --inset the initial value
VAR CurrentIndex = TablName[Index]
VAR TableBefore =
FILTER ( TablName, TablName[Index] < CurrentIndex )
VAR Y =
SUMX ( TableBefore, TablName[Y] )
VAR Z =
SUMX ( TableBefore, TablName[Z] )
RETURN
X1 + Y - Z``````  Helper III

How would these work if you can explain me?

`SUMX ( TableBefore, TablName[Y] )`
`SUMX ( TableBefore, TablName[Z] )`  Super User

Hi @shivam
Simple mathmatics

x2= x1+y1-z1
x3= x2+y2-z2 = x1+y1-z1+y2-z2 = x1 + (y1+y2) - (z1+z2) = x1 + SUMX (Y) - SUMX (Z)  