cancel
Showing results for
Did you mean:

Find everything you need to get certified on Fabric—skills challenges, live sessions, exam prep, role guidance, and more. Get started

Frequent Visitor

## Calculated column based on multiple conditions using DAX

Hello.

I could use some assistance regarding a DAX algorithm, since I'm inexperienced in algorithms of this complexity.

I have about 15k rows with data similar to the table shown below.

I wish to construct the Decision column shown below based on each week and each person and the following conditions:

- Decision should be =1 the first two days for each person and for each week (assuming the person has different values for Day_in_week_for_event (see rows with Ken).

- If the same person has an event the same day, Decision should prioritize classification A (see rows with Bob)

- If a person has 1 or more classification A in the same week, the first two A occurences in the week must be Decision =1 (see rows with Jenny).

- Decision is 0 if it isn't 1

 Person Weeknumber Day_in_week_for_event Classification Decision Bob 1 1 B 0 Bob 1 1 A 1 Jenny 2 1 B 1 Jenny 2 2 B 1 Jenny 2 3 A 1 Jenny 2 4 A 1 Jenny 2 5 A 0 Ken 2 2 A 1 Ken 2 4 B 1 Ken 2 5 B 0 Erick 3 2 B 1

Any help will be much appreciated.

Let me know if you have any questions.

1 ACCEPTED SOLUTION
Community Support

Hi, @CBXS

First, you need to add an index column to Power Query.

``````Column =
Var _N1=CALCULATE(COUNT('Table'[Index]),ALLEXCEPT('Table','Table'[Person],'Table'[Classification],'Table'[Weeknumber],'Table'[Day_in_week]))
Var _N2=CALCULATE(MIN('Table'[Index]),ALLEXCEPT('Table','Table'[Person],'Table'[Classification],'Table'[Weeknumber],'Table'[Day_in_week]))
Var _N3=CALCULATE(COUNT('Table'[Index]),ALLEXCEPT('Table','Table'[Person],'Table'[Weeknumber],'Table'[Day_in_week]))
Var _Rank=RANKX(FILTER('Table',[Person]=EARLIER('Table'[Person])&&[Weeknumber]=EARLIER('Table'[Weeknumber])),[Day_in_week],,ASC)
Return
IF(_N1>1&&[Index]=_N2,1,IF(_N3>1&&[Classification]="A",1,IF(_Rank<=2&&_N3=1,1,BLANK())))``````
``````One week more A =
Var _RankA=IF([Classification]="A",RANKX(FILTER('Table',[Person]=EARLIER('Table'[Person])&&[Weeknumber]=EARLIER('Table'[Weeknumber])&&[Classification]="A"),[Day_in_week],,ASC),BLANK())
Return
IF(_RankA<=2&&_RankA<>BLANK()&&[Column]=BLANK(),1,BLANK())``````
``````Decision = SWITCH(TRUE(),
[Column]=1,1,
[One week more A]=1,1,
0)``````

Is this the result you expect?

Best Regards,

Community Support Team _Charlotte

If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.

5 REPLIES 5
Community Support

Hi, @CBXS

You can try the following methods.

``````One week first two days =
Var _Rank=RANKX(FILTER('Table',[Person]=EARLIER('Table'[Person])&&[Weeknumber]=EARLIER('Table'[Weeknumber])),[Day_in_week_for_event],,ASC)
Return
IF(_Rank<=2,1,0)``````
``````One day more events =
Var _Countevent=CALCULATE(COUNT('Table'[Day_in_week_for_event]),FILTER('Table',[Person]=EARLIER('Table'[Person])&&[Day_in_week_for_event]=EARLIER([Day_in_week_for_event])&&[Weeknumber]=EARLIER('Table'[Weeknumber])))
Return
IF(_Countevent>1&&[Classification]="A",1,IF(_Countevent=1,[One week first two days],0))``````
``````Decision =
Var _CountA=CALCULATE(COUNT('Table'[Classification]),FILTER('Table',[Person]=EARLIER('Table'[Person])&&[Weeknumber]=EARLIER('Table'[Weeknumber])&&[Classification]="A"))
Var _RankA=IF([Classification]<>"A",BLANK(),RANKX(FILTER('Table',[Classification]="A"&&[Person]=EARLIER('Table'[Person])&&[Weeknumber]=EARLIER('Table'[Weeknumber])),[Day_in_week_for_event],,ASC))
return
IF(_CountA>=1&&_RankA<=2&&_RankA<>BLANK(),1,[One day more events])``````

Is this the result you expect?

Best Regards,

Community Support Team _Charlotte

If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.

Frequent Visitor

Almost perfect!

It doesn't look like the "One day two events" takes the weeknumber into account, as the Person= Erick row should be a 0 in the "One day two events" column, since it is the only row with weeknumber=3.

Additionally, i forgot to mention another condition. If there are multiple events for a person on the same day in the same week, the Decision should be 1 in only one of those rows. Your code does this when the two events have different classification, but not if the classification is the same. It doesn't matter which row that gets Decision = 1.

See the desired result in the last two rows with Person = Erick

 Person Weeknumber Day_in_week Classification Decision Bob 1 1 B 0 Bob 1 1 A 1 Jenny 2 1 B 1 Jenny 2 2 B 1 Jenny 2 3 A 1 Jenny 2 4 A 1 Jenny 2 5 A 0 Ken 2 2 A 1 Ken 2 4 B 1 Ken 2 5 B 0 Erick 3 2 B 1 Erick 3 2 B 0

Thank you so much for helping me with my problem!

Community Support

Hi, @CBXS

First, you need to add an index column to Power Query.

``````Column =
Var _N1=CALCULATE(COUNT('Table'[Index]),ALLEXCEPT('Table','Table'[Person],'Table'[Classification],'Table'[Weeknumber],'Table'[Day_in_week]))
Var _N2=CALCULATE(MIN('Table'[Index]),ALLEXCEPT('Table','Table'[Person],'Table'[Classification],'Table'[Weeknumber],'Table'[Day_in_week]))
Var _N3=CALCULATE(COUNT('Table'[Index]),ALLEXCEPT('Table','Table'[Person],'Table'[Weeknumber],'Table'[Day_in_week]))
Var _Rank=RANKX(FILTER('Table',[Person]=EARLIER('Table'[Person])&&[Weeknumber]=EARLIER('Table'[Weeknumber])),[Day_in_week],,ASC)
Return
IF(_N1>1&&[Index]=_N2,1,IF(_N3>1&&[Classification]="A",1,IF(_Rank<=2&&_N3=1,1,BLANK())))``````
``````One week more A =
Var _RankA=IF([Classification]="A",RANKX(FILTER('Table',[Person]=EARLIER('Table'[Person])&&[Weeknumber]=EARLIER('Table'[Weeknumber])&&[Classification]="A"),[Day_in_week],,ASC),BLANK())
Return
IF(_RankA<=2&&_RankA<>BLANK()&&[Column]=BLANK(),1,BLANK())``````
``````Decision = SWITCH(TRUE(),
[Column]=1,1,
[One week more A]=1,1,
0)``````

Is this the result you expect?

Best Regards,

Community Support Team _Charlotte

If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.

Frequent Visitor

It works as intended for the examples shown above.

Although there are still different combinations where the Decision column isn't the desired result:

A person should only have two Decision = 1 for a given week if the classification is the same through the week, see the desired result below (Chris and Derp):

 Person Weeknumber Day_in_week Classification Decision Bob 1 1 B 0 Bob 1 1 A 1 Jenny 2 1 B 1 Jenny 2 2 B 1 Jenny 2 3 A 1 Jenny 2 4 A 1 Jenny 2 5 A 0 Ken 2 2 A 1 Ken 2 4 B 1 Ken 2 5 B 0 Erick 3 2 B 1 Erick 3 2 B 0 Jenny 2 6 A 0 Jenny 2 5 B 0 Chris 6 1 A 1 Chris 6 1 A 0 Chris 6 5 A 1 Chris 6 5 A 0 Chris 6 6 A 0 Chris 6 6 A 0 Chris 6 7 A 0 Chris 6 7 A 0 Derp 7 1 B 1 Derp 7 1 B 0 Derp 7 5 B 1 Derp 7 5 B 0 Derp 7 6 B 0 Derp 7 6 B 0 Derp 7 7 B 0 Derp 7 7 B 0

I attempted to edit your code to achieve the desired result, but I am not experienced enough in DAX, unfortunately.

Frequent Visitor

@v-zhangti are you able to assist me with the request above?

It would be much appreciated !

Announcements

#### Europe’s largest Microsoft Fabric Community Conference

Join the community in Stockholm for expert Microsoft Fabric learning including a very exciting keynote from Arun Ulag, Corporate Vice President, Azure Data.

If you love stickers, then you will definitely want to check out our Community Sticker Challenge!

#### Power BI Monthly Update - July 2024

Check out the July 2024 Power BI update to learn about new features.

#### Fabric Community Update - July 2024

Find out what's new and trending in the Fabric Community.

Top Solution Authors
Top Kudoed Authors