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Hola,
Me podeis ayudar en una formula para una columna que devolva una fecha (mating Date) para egual primary ID y service >1
Algo como "return (mating date , if primary identidy are the same && service >1)
Espero haber podido explicar
Muchas gracias!
Envio tabla de ejemplo.
PrimaryIdentity | FarmNumber | DateOfBirth | EntryDate | SoldDate | Farrowings | Cycle | Service | X | MatingDate | ||
3947 | 752 | 04/04/2017 | 04/12/2017 | 20/05/2021 | 8 | 9 | 1 | 1 | 04/01/2021 | 04/01/2021 | |
3950 | 752 | 04/04/2017 | 04/12/2017 | 10/06/2021 | 8 | 9 | 1 | 1 | 25/01/2021 | 25/01/2021 | |
3995 | 752 | 07/04/2017 | 11/09/2017 | 27/05/2021 | 7 | 8 | 1 | 1 | 06/01/2021 | 06/01/2021 | |
4008 | 752 | 27/04/2017 | 09/10/2017 | 17/06/2021 | 7 | 8 | 1 | 1 | 25/01/2021 | 25/01/2021 | |
4020 | 752 | 27/04/2017 | 09/10/2017 | 10/06/2021 | 7 | 8 | 1 | 1 | 18/01/2021 | 18/01/2021 | |
4025 | 752 | 27/04/2017 | 09/10/2017 | 10/06/2021 | 7 | 8 | 1 | 1 | 21/01/2021 | 21/01/2021 | |
4039 | 752 | 06/07/2017 | 11/12/2017 | 10/06/2021 | 7 | 8 | 1 | 1 | 25/01/2021 | 25/01/2021 | |
4040 | 752 | 06/07/2017 | 11/12/2017 | 18/11/2021 | 7 | 8 | 1 | 1 | 02/02/2021 | 02/02/2021 | |
4042 | 752 | 06/07/2017 | 11/12/2017 | 08/07/2021 | 7 | 8 | 1 | 1 | 25/01/2021 | 25/01/2021 | |
4042 | 752 | 06/07/2017 | 11/12/2017 | 08/07/2021 | 7 | 8 | 2 | 1 | 20/02/2021 | -> | 25/01/2021 |
4053 | 752 | 06/07/2017 | 11/12/2017 | 22/02/2021 | 6 | 7 | 1 | 1 | 22/01/2021 | 22/01/2021 | |
4054 | 752 | 06/07/2017 | 11/12/2017 | 10/06/2021 | 6 | 7 | 1 | 1 | 15/01/2021 | 15/01/2021 | |
4054 | 752 | 06/07/2017 | 11/12/2017 | 10/06/2021 | 6 | 7 | 2 | 1 | 07/02/2021 | -> | 15/01/2021 |
4059 | 752 | 06/07/2017 | 11/12/2017 | 01/07/2021 | 6 | 7 | 1 | 1 | 08/02/2021 | 08/02/2021 | |
4065 | 752 | 06/07/2017 | 11/12/2017 | 22/07/2021 | 6 | 7 | 1 | 1 | 01/03/2021 | 01/03/2021 | |
41749 | 34 | 02/07/2017 | 29/11/2017 | 08/08/2022 | 10 | 11 | 1 | 3 | 10/03/2022 | 10/03/2022 | |
41854 | 34 | 03/07/2017 | 06/12/2017 | 26/07/2022 | 10 | 11 | 1 | 2 | 09/03/2022 | 09/03/2022 | |
041731@1 | 34 | 02/07/2017 | 29/11/2017 | 29/03/2022 | 10 | 11 | 1 | 3 | 09/03/2022 | 09/03/2022 |
Solved! Go to Solution.
Hi @DBrito79 ,
I have created a simple sample , please refer to my pbix file to see if it helps you.
Create 2 measures.
Measure = var _1=CALCULATE(COUNT('Table'[PrimaryIdentity]),FILTER(ALL('Table'),'Table'[PrimaryIdentity]=SELECTEDVALUE('Table'[PrimaryIdentity])))
return
IF(_1>1&&MAX('Table'[Service])>1,BLANK(),MAX('Table'[MatingDate]))
Measure 2 = MAXX(FILTER(ALL('Table'),'Table'[PrimaryIdentity]=SELECTEDVALUE('Table'[PrimaryIdentity])),[Measure])
Or 2 columns.
Column = var _1=CALCULATE(COUNT('Table'[PrimaryIdentity]),FILTER('Table','Table'[PrimaryIdentity]=EARLIER('Table'[PrimaryIdentity])))
var _2=IF(_1>1&&'Table'[Service]>1,BLANK(),'Table'[MatingDate])
return _2
Column 2 = MAXX(FILTER('Table','Table'[PrimaryIdentity]=EARLIER('Table'[PrimaryIdentity])),'Table'[Column])
How to Get Your Question Answered Quickly
If it does not help, please provide more details with your desired output and pbix file without privacy information (or some sample data) .
Best Regards
Community Support Team _ Rongtie
If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.
Hello!
Yes it works and helps a lot! And also helps for another similar formula that I need after.
Thank you very much. You are a genius!
Best Regards
Diogo
Hi @DBrito79 ,
I have created a simple sample , please refer to my pbix file to see if it helps you.
Create 2 measures.
Measure = var _1=CALCULATE(COUNT('Table'[PrimaryIdentity]),FILTER(ALL('Table'),'Table'[PrimaryIdentity]=SELECTEDVALUE('Table'[PrimaryIdentity])))
return
IF(_1>1&&MAX('Table'[Service])>1,BLANK(),MAX('Table'[MatingDate]))
Measure 2 = MAXX(FILTER(ALL('Table'),'Table'[PrimaryIdentity]=SELECTEDVALUE('Table'[PrimaryIdentity])),[Measure])
Or 2 columns.
Column = var _1=CALCULATE(COUNT('Table'[PrimaryIdentity]),FILTER('Table','Table'[PrimaryIdentity]=EARLIER('Table'[PrimaryIdentity])))
var _2=IF(_1>1&&'Table'[Service]>1,BLANK(),'Table'[MatingDate])
return _2
Column 2 = MAXX(FILTER('Table','Table'[PrimaryIdentity]=EARLIER('Table'[PrimaryIdentity])),'Table'[Column])
How to Get Your Question Answered Quickly
If it does not help, please provide more details with your desired output and pbix file without privacy information (or some sample data) .
Best Regards
Community Support Team _ Rongtie
If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.
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