Forum Discussion
Sum by two groups
Hi experts,
Would you please help me sum the total by both type and class
End result should be
HS--> 1000
TM --> 1520
| Class | Type | Total |
| A | HS | 500 |
| A | HS | 500 |
| Z | HS | 500 |
| Z | HS | 500 |
| Z | HS | 500 |
| Z | HS | 500 |
| C | TM | 760 |
| L | TM | 760 |
| . | . | . |
| . | . | . |
| . | . | . |
| . | . | . |
Anonymous So tweak your measure like below:
Measure = CALCULATE(SUM('Table'[Total]),ALLEXCEPT('Table','Table'[Class]))
6 Replies
- selimovdMost Valuable Professional
Hey Anonymous ,
you can just create a matrix and put the Type in the rows and the total in the values. Then it will sum by Type.
Otherwise you could create measures:
Sum HS = CALCULATE( SUM( myTable[Total] ), myTable[Type] = "HS" )and for TM:
Sum TM = CALCULATE( SUM( myTable[Total] ), myTable[Type] = "TM" )The measures set the filter of the type to HS or TM and for that reason you will always get the sum for the corresponding type.
If you need any help please let me know.If I answered your question I would be happy if you could mark my post as a solution ✔️ and give it a thumbs up 👍Best regardsDenisBlog: WhatTheFact.biFollow me: twitter.com/DenSelimovic- AnonymousNot applicable
This won't work as it will return 3000 for HS as it is not considering the Class in the equation.
HS should be 1000
- Tahreem24Super User
Anonymous Create a measure like below:
Measure = CALCULATE(SUM('Table'[Total]),ALLEXCEPT('Table','Table'[Type]))- AnonymousNot applicable
This won't work as it will return 3000 for HS as it is not considering the Class in the equation.
HS should be 1000
- Tahreem24Super User
Anonymous So tweak your measure like below:
Measure = CALCULATE(SUM('Table'[Total]),ALLEXCEPT('Table','Table'[Class]))
- AnonymousNot applicable
Hi Anonymous ,
Does the replies above solve your problem? If it has been solved, please mark the correct reply as the standard answer to help the other members find it more quickly.Thank you very much for your kind cooperation!
Hope it helps,
Community Support Team _ CaitlynIf this post helps then please consider Accept it as the solution to help the other members find it more quickly.