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Hello,
Quick insights is a really cool tool, but i meet a pb in it.
I want that the quick insights perform the calcul on avaerage value of diffrent labels, but today, quick insights always perform the calcul on sum.
For some types of values, sum is good, ex: population
But for some types of values, sum is useless, ex. the price.
Some konw how to set the method on average instead of sum.
Thanks a lot
Solved! Go to Solution.
It's not supported to change the aggregation in Quick Insights. It always renders data with Sum. You may submit a feature request on idea.
Regards,
It's not supported to change the aggregation in Quick Insights. It always renders data with Sum. You may submit a feature request on idea.
Regards,
Thanks for your reply, in this case, i will submit a feature request.
For my concret case, i will try to do some datamining by python or R
Hello,
Quick insights is a really cool tool, but i meet a pb in it.
I want that the quick insights perform the calcul on avaerage value of diffrent labels, but today, quick insights always perform the calcul on sum.
For some types of values, sum is good, ex: population
But for some types of values, sum is useless, ex. the price.
Some konw how to set the method on average instead of sum.
Thanks a lot
Hello,
Quick insights is a really cool tool, but i meet a pb in it.
I want that the quick insights perform the calcul on avaerage value of diffrent labels, but today, quick insights always perform the calcul on sum.
For some types of values, sum is good, ex: population
But for some types of values, sum is useless, ex. the price.
Some konw how to set the method on average instead of sum.
Thanks a lot
Hello,
Quick insights is a really cool tool, but i meet a pb in it.
I want that the quick insights perform the calcul on avaerage value of diffrent labels, but today, quick insights always perform the calcul on sum.
For some types of values, sum is good, ex: population
But for some types of values, sum is useless, ex. the price.
Some konw how to set the method on average instead of sum.
Thanks a lot
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