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py1029's avatar
py1029
Frequent Visitor
4 years ago
Solved

Calculate the achievement

Hi,

 

I have a problem when calculating the achievement. There are 3 benchmarks to measure the performance of an employee which are threshold, target and excellence. I want to use the "Target" as the only benchmarks when calculating the achievement.
For case 1, the "Excellence" value is greater than the "Threshold" value, I can directly use [Actual]/[Target] = Achievement.

For case 2, the "Excellence" value is smaller than the "Threshold" value, if use [Actual]/[Target] directly, will give me a wrong info which the Achievement will be only 70% instead of 130%. May refer to the sample below:

Does anyone can advise on the calculation of achievement for Case 2?

 

Thanks!

 
  • Anonymous's avatar
    Anonymous
    4 years ago

    Hi py1029,

    You can try If function to show different results in Case1 and Case2.

    For reference: IF

    Achievement = 
    VAR _CASE1 =
        DIVIDE ( 'Table'[Actual], 'Table'[Target] )
    VAR _CASE2 =
        DIVIDE (
            'Table'[Excellence] - 'Table'[Actual] + 'Table'[Threshold],
            'Table'[Target]
        )
    RETURN
        IF ( 'Table'[Excellence] > 'Table'[Threshold], _CASE1, _CASE2 )

    Result:


    Best Regards,
    Rico Zhou

     

    If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.

     

1 Reply

  • Anonymous's avatar
    Anonymous
    Not applicable

    Hi py1029,

    You can try If function to show different results in Case1 and Case2.

    For reference: IF

    Achievement = 
    VAR _CASE1 =
        DIVIDE ( 'Table'[Actual], 'Table'[Target] )
    VAR _CASE2 =
        DIVIDE (
            'Table'[Excellence] - 'Table'[Actual] + 'Table'[Threshold],
            'Table'[Target]
        )
    RETURN
        IF ( 'Table'[Excellence] > 'Table'[Threshold], _CASE1, _CASE2 )

    Result:


    Best Regards,
    Rico Zhou

     

    If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.