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can any one help me to write the script i want to get the result below
From Date Table and Data table
the rule is if sum of sales per week >=15 then it's 1, then i will need to sum the week based on period.
i got this by if( sum(sales)>=15,1,0), but i don't know how to sum it again by period
Solved! Go to Solution.
Hi @markcabantog ,
According to your description, here's my solution.
1.The two tables are related with Date column.
2.Create a calculated column in Data table.
WeekNo = RELATED('Date'[WeekNo])
2.Create a measure.
Measure =
VAR _T =
ADDCOLUMNS (
'Data',
"Flag",
IF (
SUMX (
FILTER ( 'Data', 'Data'[WeekNo] = EARLIER ( 'Data'[WeekNo] ) ),
'Data'[Sales]
) > 15,
1,
0
)
/ COUNTROWS (
FILTER (
'Data',
'Data'[Veg] = EARLIER ( 'Data'[Veg] )
&& 'Data'[WeekNo] = EARLIER ( 'Data'[WeekNo] )
)
)
)
RETURN
SUMX ( _T, [Flag] )
Get the correct result:
I attach my sample below for your reference.
Best Regards,
Community Support Team _ kalyj
If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.
Hi @markcabantog ,
According to your description, here's my solution.
1.The two tables are related with Date column.
2.Create a calculated column in Data table.
WeekNo = RELATED('Date'[WeekNo])
2.Create a measure.
Measure =
VAR _T =
ADDCOLUMNS (
'Data',
"Flag",
IF (
SUMX (
FILTER ( 'Data', 'Data'[WeekNo] = EARLIER ( 'Data'[WeekNo] ) ),
'Data'[Sales]
) > 15,
1,
0
)
/ COUNTROWS (
FILTER (
'Data',
'Data'[Veg] = EARLIER ( 'Data'[Veg] )
&& 'Data'[WeekNo] = EARLIER ( 'Data'[WeekNo] )
)
)
)
RETURN
SUMX ( _T, [Flag] )
Get the correct result:
I attach my sample below for your reference.
Best Regards,
Community Support Team _ kalyj
If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.
Hi @markcabantog ,
You can directly write measure as below:-
Measure = IF(SUM('Table (2)'[sales])>= 15,1,0)
Output:-
Refer a file below:-
Best Regards,
Samarth
If this post helps, please consider accepting it as the solution to help the other members find it more quickly.
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