ranking with identical values

[stijn007]

Hello, 

I want a chart with the top 10 items shown. 

In my legend I have the treinnumbers that were selected. 

Value: Count of train numbers. 

I created a measure 

Top 10 treinen = RANKX(ALLSELECTED('Problemen Werken FBMZ'[Treinnummer]);CALCULATE(COUNT('Problemen Werken FBMZ'[Treinnummer])))

This measure is ranking but the trains who have an identical count (eg 1) are ale ranked the same way.

Now there is shown 13 trains instead of my top 10.

[v-juanli-msft]

Hi @stijn007 

Create a measure

Final Rank = 
RANKX (
    ALLSELECTED('Table'),
    RANKX ( ALLSELECTED('Table'),CALCULATE(COUNT('Table'[number])),,DESC,Dense)
        + DIVIDE (
            RANKX (ALLSELECTED('Table'),CALCULATE(MAX('Table'[number])),,ASC,Dense),
            COUNTROWS(ALLSELECTED('Table'))
        ),,ASC,Dense
)

Best Regards
Maggie

Community Support Team _ Maggie Li
If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.

[stijn007]

When I tried, the ranking is different when I order in the column "Final Rank"

Somewhere it has to order in column Count. 

[stijn007]

@v-juanli-msft 

[v-juanli-msft]

Hi @stijn007 

How do you create that incorrect measure?

Could you show me some screenshots about your columns and measure?

Do you want the final rank to be a column?

Best Regards
Maggie

[stijn007]

@v-juanli-msft 

[v-juanli-msft]

Hi @stijn007 

Is this problem sloved? 

If it is sloved, could you kindly accept it as a solution to close this case?

If not, please let me know.

Best Regards

Maggie

[v-juanli-msft · Accepted solution]

Hi @stijn007 

I notice this line

You write countrows(allselected(table[column]))

Please correct it by the formula below

countrows(allselected(table))

Best Regards
Maggie

Community Support Team _ Maggie Li
If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.