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bsz412
Helper III
Helper III

create date from a variable

HI, 

I have created a variable called _lastdate. 

I would need another variable that shows _lastdate minus 1 month, so if _lastdate is 15 July 2022, _1month should be 15 June 2022.

Formula below gives an error message:

bsz412_0-1658319262561.png

 

1 ACCEPTED SOLUTION
VahidDM
Super User
Super User

Hi @bsz412 

 

Try to update your code like this:
CHrn vs Last = 
Var _Lastdate= calculte(...)
Var _Last_Year = year(_Lastdate)
Var _Last_Month = month(_Lastdate)
Var _Last_Day = Day(_Lastdate)
Var _1month=Date(_Last_Year,_Last_Month-1,_Last_Day)

 

If this post helps, please consider accepting it as the solution to help the other members find it more quickly.

Appreciate your Kudos!! 

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View solution in original post

2 REPLIES 2
VahidDM
Super User
Super User

Hi @bsz412 

 

Try to update your code like this:
CHrn vs Last = 
Var _Lastdate= calculte(...)
Var _Last_Year = year(_Lastdate)
Var _Last_Month = month(_Lastdate)
Var _Last_Day = Day(_Lastdate)
Var _1month=Date(_Last_Year,_Last_Month-1,_Last_Day)

 

If this post helps, please consider accepting it as the solution to help the other members find it more quickly.

Appreciate your Kudos!! 

Badges.jpg

LinkedIn | Twitter | Blog | YouTube 

 

 

Thank you @VahidDM , it works ! 🙂

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