Starting December 3, join live sessions with database experts and the Microsoft product team to learn just how easy it is to get started
Learn moreGet certified in Microsoft Fabric—for free! For a limited time, get a free DP-600 exam voucher to use by the end of 2024. Register now
HI,
I have created a variable called _lastdate.
I would need another variable that shows _lastdate minus 1 month, so if _lastdate is 15 July 2022, _1month should be 15 June 2022.
Formula below gives an error message:
Solved! Go to Solution.
Hi @bsz412
Try to update your code like this:
CHrn vs Last =
Var _Lastdate= calculte(...)
Var _Last_Year = year(_Lastdate)
Var _Last_Month = month(_Lastdate)
Var _Last_Day = Day(_Lastdate)
Var _1month=Date(_Last_Year,_Last_Month-1,_Last_Day)
If this post helps, please consider accepting it as the solution to help the other members find it more quickly.
Appreciate your Kudos!!
LinkedIn | Twitter | Blog | YouTube
Hi @bsz412
Try to update your code like this:
CHrn vs Last =
Var _Lastdate= calculte(...)
Var _Last_Year = year(_Lastdate)
Var _Last_Month = month(_Lastdate)
Var _Last_Day = Day(_Lastdate)
Var _1month=Date(_Last_Year,_Last_Month-1,_Last_Day)
If this post helps, please consider accepting it as the solution to help the other members find it more quickly.
Appreciate your Kudos!!
LinkedIn | Twitter | Blog | YouTube
Starting December 3, join live sessions with database experts and the Fabric product team to learn just how easy it is to get started.
March 31 - April 2, 2025, in Las Vegas, Nevada. Use code MSCUST for a $150 discount! Early Bird pricing ends December 9th.
User | Count |
---|---|
87 | |
83 | |
82 | |
65 | |
49 |
User | Count |
---|---|
135 | |
111 | |
100 | |
65 | |
62 |