Forum Discussion
Working with Count,summarize and filter
So I have a column EID and status,
I only want to filter the completed and summarize it based on EID and after will count the rows.
I got lost here don't know where would I put the summarize function
| EID | Status |
| 1 | Pending |
| 2 | Completed |
| 2 | Completed |
| 3 | Completed |
Output: Completed = 2
Hello @Kalachuchi
You can use this measure to get different EID values:
Cnt of Completed = CALCULATE(DISTINCTCOUNT('Table'[EID]),FILTER('Table','Table'[Status] = "Completed"))
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If I helped, please accept the solution and give congratulations! 😀
6 Replies
- mohammedadnantImpactful Individual
This will help,
Completed Count = CALCULATE( DISTINCTCOUNT(CompleteTable[EID]),FILTER('CompleteTable','CompleteTable'[Status]="Completed"))Thanks and hit the like button,Mohammed Adnan - Greg_DecklerCommunity Champion
Kalachuchi - Try -
Measure = COUNTROWS(DISTINCT(FILTER('Table1','Table1'[Status]="Completed"))) or Measure = COUNTROWS(SUMMARIZE(FILTER('Table1','Table1'[Status]="Completed"),[EID])) - lkalawskiResident Rockstar
Hello @Kalachuchi
You can use this measure to get different EID values:
Cnt of Completed = CALCULATE(DISTINCTCOUNT('Table'[EID]),FILTER('Table','Table'[Status] = "Completed"))
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If I helped, please accept the solution and give congratulations! 😀 - TomMartensSuper User
Hey Kalachuchi ,
wondering if this more simpler measure is sufficient:
Measure = CALCULATE( DISTINCTCOUNT('Table'[EID]) , 'Table'[Status] = "Completed" )Hopefully, this provides what you are looking for.
Regards,
Tom
- amitchandakSuper User
Kalachuchi , Try like
COUNTX(summarize(FILTER('Table1','Table1'[Status]="Completed"),'Table1'[Status]),[Status])
- v-easonf-msftCommunity Support
Hi , Kalachuchi
amitchandak ‘s formula needs to be slightly adjusted.
Measure = COUNTX(summarize(FILTER('Table1','Table1'[Status]="Completed"),'Table1'[EID]),[EID])If your problem has been solved,please mark the helpful replies or add your reply as Answered to close this thread.
It will help other community members easily find the solution when they get the similar issue.Best Regards,
Community Support Team _ Eason