Forum Discussion
Weekday Last Year Comparison
Hi Vvelarde, yep you're right it was 3th July 2015 I confused it with August.
About your answer, It work for this year, but what happen if the year is a leap-year? It has 366 days and a normal year has 365. It have to be dynamic or something like that. My solution have to work to infinity and beyond
- Anonymous10 years agoNot applicable
One solution that came to mind is on the date (calendar) table
1. create a column WeekNo= Weeknum([Calendar[FullDate]) ( Full Date is the Date column in DD/MM/YYYY format)
2. Create a column WeekDayNo = WeekDay(Calendar([FullDate])
3. Create a column Year = Year(Calendar[FullDate])
4. Create a column DWY = ([WeekDayNo]*100+[WeekNo])*10000+[Year] . This will create numbers like 5012015, 5012016, etc. etc
depending on the Date.
5. Join your fact table to the Calendar table
6. Create a measure sya for Sales = sum(Facttable[SalesAmount])
7. Create a measure to compute the sales for same day same week last year as
SalesLYDWY = Calculate([Sales], Filter(ALL(Calendar),Calendar[DWY] = Max( Calendar[DWY]) -1 ))
8. You should now be able to view the Sales and SalesLYDWY side by side.
Sample of what I did
Column Labels 1 2 3 4 5 6 7 Row Labels Sales2 SWLY Sales2 SWLY Sales2 SWLY Sales2 SWLY Sales2 SWLY Sales2 SWLY Sales2 SWLY 2015 24 41 43 25 45 47 49 51 53 55 57 26 59 61 63 65 67 69 71 27 73 2015 Total 177 108 112 116 120 165 171 2016 24 41 43 25 41 45 43 47 45 49 47 51 49 53 51 55 53 57 26 55 59 57 61 59 63 61 65 63 67 65 69 67 71 27 69 73 71 73 2016 Total 165 171 177 108 112 116 120 This should work for all years and weeks for eternity.
If this solves your requirement please accept this as a solution and also give KUDOS.
Cheers
CheenuSing
- Mikkelnaes8 years agoHelper I
Dear Anonymous,
Thank you, this is great.
The only challenge I have is that my last year based on your number. 7 has one drawback.
Net Sales LY test = CALCULATE([Net Sales test];FILTER(ALL('TestDWH Date');'TestDWH Date'[DWY] = MAX('TestDWH Date'[DWY])-1))
When I have it on days, i.e. monday, tuesday etc, my "total" row in f.ex. a table only show value for sunday LY. Do I need any IF statement?
Thank you,
Mikkel
- Anonymous8 years agoNot applicable
Hi Mikkelnaes
Could you please post your pbix in one drive / google drive and share the link.
Please also explain what is not working correctly.
Cheers
CheenuSing
- VijayReddy8 years agoFrequent Visitor
Hi CheenuSingh,
Just wondering why you would multiply WeekDayNo by 100? Please could you explain?
Thank you
Vijay
- Anonymous8 years agoNot applicable
Hi VijayReddy
As we want to compare by day by week and year, we had to use a formula to generate the unique number combination.
So,
Create a column DWY = ([WeekDayNo]*100+[WeekNo])*10000+[Year] . This will create numbers like 5012015, 5012016, etc. etc
depending on the Date.
When we use the measure to compute the sales for same day same week last year as
SalesLYDWY = Calculate([Sales], Filter(ALL(Calendar),Calendar[DWY] = Max( Calendar[DWY]) -1 ))
it becomes simpler to just substract 1 from the current selected calendar year.
Cheers
CheenuSing
- Anonymous8 years agoNot applicable
Hello,
I have used your solution, it works great. The only issue is that now I am trying to aggregate it per month as well.
To get the sales for last year I am using this:
Sales Last Year = SUMX(VALUES('Calendar'[DWY]),Calculate(SUM('Sales & Tickets'[Sales]), Filter(ALL('Calendar'),Calendar[DWY] = MAX(Calendar[DWY])-1 )))
Unfortunately when drilling through from day to month data is slightly inaccurate. Any idea how to solve this issue?
Again, thank you for your previous solution, it was extremely helpful!
- Anonymous8 years agoNot applicable
For those interested, I replaced the MAX by the function EARLIER that I just discovered (which by my understanding we could actually almost always call current row).
- donsvensen10 years agoSkilled Sharer
Hi
A leep year still has 52 weeks so you will hit the same weekday.
But in years with 53 weeks you have to decide whether you want to go 364 days (52*7) back or (53*7) - the easy way is always to use 364 (52*7) :-)
br
Erik