Forum Discussion
Urgent- Simple formula but complex issue
Hello,
I would like to express the column " % as of NNS "( which is simply Num / Den) in function of the the category . However when I do put the value in a graphe it will simply sum the two value that we have for VMHS % 24 % + 64% = 88 % ( screen 1) which are not correct because MHS Professional has much lower value than VMHS VP ( not taking the weight into consideration) ( screen 2 for weight Num , Den columns) .
I would like to create another column which takes only categories , for exemple it will give us
Num for VMHS = 608 + 12
Den for VMhs = 50 + 983
% as of NNS = (608 + 12 ) / ( 50 + 983 ) = 61 % and NOT 88%
such that when we do use a graphe using category ( Y Axis ) and % as of NNS as (X axis ) it will give us the right values.
It does not aggreagte correctly
Hi Anonymous ,
Can you share the data by text or table than screenshot.
Or you can try this dax to do that:
Column = VAR _1 = CALCULATE ( DIVIDE ( SUM ( 'Table'[Num] ), SUM ( 'Table'[Den] ) ), FILTER ( 'Table', [KPI] = EARLIER ( 'Table'[KPI] ) && [Period Type] = EARLIER ( 'Table'[Period Type] ) && [Cluster] = EARLIER ( 'Table'[Cluster] ) && [category] = "vmhs" ) ) VAR _2 = DIVIDE ( [Num], [Den] ) RETURN IF ( [category] = "vmhs", _1, _2 )Result:
Pbix in the end you can refer.
Best Regards
Community Support Team _ chenwu zhu
If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.
1 Reply
- v-chenwuz-msft
Community Support
Hi Anonymous ,
Can you share the data by text or table than screenshot.
Or you can try this dax to do that:
Column = VAR _1 = CALCULATE ( DIVIDE ( SUM ( 'Table'[Num] ), SUM ( 'Table'[Den] ) ), FILTER ( 'Table', [KPI] = EARLIER ( 'Table'[KPI] ) && [Period Type] = EARLIER ( 'Table'[Period Type] ) && [Cluster] = EARLIER ( 'Table'[Cluster] ) && [category] = "vmhs" ) ) VAR _2 = DIVIDE ( [Num], [Den] ) RETURN IF ( [category] = "vmhs", _1, _2 )Result:
Pbix in the end you can refer.
Best Regards
Community Support Team _ chenwu zhu
If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.