Summarize differences between every 5 years?

Hi  Anonymous ,

I created some data:

Here are the steps you can follow：

1. Create calculated column.

Year = YEAR('Table'[Date])

Flag =
var _today=TODAY()
var _yeartoday=YEAR(_today)
var _round=
ROUNDUP(
('Table'[Year] - _yeartoday ) /5,0)
return
IF(
    'Table'[Year]=_yeartoday,-1,_round)

Title =
var _minyear=MINX(FILTER(ALL('Table'),'Table'[Flag]=EARLIER('Table'[Flag])),[Year])
var _minx=MINX(FILTER(ALL('Table'),'Table'[Flag]=EARLIER('Table'[Flag])+1),[Year])
var _indexmax=MAXX(ALL('Table'),[Flag])
return
IF(
    'Table'[Flag]=_indexmax,
   YEAR(TODAY()) &" and "& _minyear,
 _minx &" and "& _minyear
)

Sum all =
var _minyear=MINX(FILTER(ALL('Table'),'Table'[Flag]=EARLIER('Table'[Flag])),[Year])
var _minx=MINX(FILTER(ALL('Table'),'Table'[Flag]=EARLIER('Table'[Flag])+1),[Year])
var _indexmax=MAXX(ALL('Table'),[Flag])
return
IF(
    'Table'[Flag]=_indexmax,
    SUMX(FILTER(ALL('Table'),[Year]>=_minyear &&[Year]<=YEAR(TODAY())),[Value]),
    SUMX(FILTER(ALL('Table'),[Year]>=_minyear &&[Year]<=_minx),[Value])
)

2. Create calculated table.

Table 2 =
SUMMARIZE('Table','Table'[Title],'Table'[Sum all])

3. Result:

 

Best Regards,

Liu Yang

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