Forum Discussion
Subtracting a filter value
Hi !
I am trying to create a measure which subtracts filtered value based on month (Current month - previous month.)
Sum of the Actual Value for June where Type = "$" - Sum of the Actual Value for Previous Month (May) where Type = "Est"
i.e. 3,300 - 1,600=700
| Segment | Country | Product | Discount Band | Value | Budget/Fcst/Actual | Type | Date | Month Number | Month Name | Year |
| Midmarket | France | Carretera | None | 2500 | Actual | $ | 6/1/2014 | 6 | June | 2014 |
| Midmarket | Germany | Carretera | None | 800 | Actual | $ | 6/1/2014 | 6 | June | 2014 |
| Midmarket | Mexico | Carretera | None | 1500 | Actual | Est. | 5/1/2014 | 5 | May | 2014 |
| Midmarket | Germany | Montana | None | 100 | Actual | Est. | 5/1/2014 | 5 | May | 2014 |
Thank you.
Hi lab
You can try creating following measures:
CM Value= calculate(sum('TableName'[Value]), 'TableName'[Type] = "$")
PM Value = calculate(sum('TableName'[Value]), 'TableName'[Type] = "Est.", 'TableName'[Month Number] = 'TableName'[Month Number] - 1)
Diff Value = [CM Value] - PM Value]Thanks,
Dheeraj
2 Replies
- dkaushikResolver II
Hi lab
You can try creating following measures:
CM Value= calculate(sum('TableName'[Value]), 'TableName'[Type] = "$")
PM Value = calculate(sum('TableName'[Value]), 'TableName'[Type] = "Est.", 'TableName'[Month Number] = 'TableName'[Month Number] - 1)
Diff Value = [CM Value] - PM Value]Thanks,
Dheeraj
- labFrequent Visitor
Thanks !