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Animal |
Bear |
Dog |
Bear |
Cat |
Tiger |
Based on the sample table above, supposedly I would have 4 distinct values and 0 unique due to the "Bear" on first row is the same as the "Bear" in the third row. However what I am getting is 4 distinct values and 1 unique in which the unique is one of the "Bear" in any row. The spelling and capitilaztion both are the same yet how do I group it as a single "Bear"? Because when accessing in slicer, there will be two options of "Bear".
Solved! Go to Solution.
Hi @syeena ,
Ideally, it should not happen if everything is the same then it should show only 4 values in the slicer(one value for bear). However, you can keep unique values in the slicer by creating a separate table for unique values as below:-
Table_slicer = DISTINCT('Table'[Animal])
Connect this table to your animal column and use the table_slicer column as the slicer column.
Best Regards,
Samarth
If this post helps, please consider accepting it as the solution to help the other members find it more quickly.
Appreciate your Kudos!!
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Hi @syeena ,
Ideally, it should not happen if everything is the same then it should show only 4 values in the slicer(one value for bear). However, you can keep unique values in the slicer by creating a separate table for unique values as below:-
Table_slicer = DISTINCT('Table'[Animal])
Connect this table to your animal column and use the table_slicer column as the slicer column.
Best Regards,
Samarth
If this post helps, please consider accepting it as the solution to help the other members find it more quickly.
Appreciate your Kudos!!
Connect on Linkedin