Starting December 3, join live sessions with database experts and the Microsoft product team to learn just how easy it is to get started
Learn moreGet certified in Microsoft Fabric—for free! For a limited time, get a free DP-600 exam voucher to use by the end of 2024. Register now
Hi everyone,
I have a table similar to the sample below
Date | Route no. | Customer | Route Cost A | Route Cost B | Route Cost C |
01-Oct | 1 | A | 18,000 | ||
01-Oct | 1 | A | |||
01-Oct | 1 | A | |||
01-Oct | 1 | A | |||
01-Oct | 1 | A | |||
03-Oct | 2 | B | 21,000 | 444.01 | 166.50 |
03-Oct | 2 | A | |||
03-Oct | 2 | A | |||
03-Oct | 2 | C | |||
03-Oct | 2 | C | |||
03-Oct | 2 | A | |||
03-Oct | 2 | B | |||
04-Oct | 3 | A | 15,725.27 | 620.73 | |
04-Oct | 3 | A | |||
04-Oct | 3 | A | |||
04-Oct | 3 | C | |||
04-Oct | 3 | C |
What I'm trying to do is return the total cost of each customer, based on 1) the selected customer, and 2) the time slicer.
For example, if I choose customer A and set slicer to 01/10/2020 - 03/10/2020, I would get 18000 + 21000 = 39000 as result.
Your help would be much appreciated!
Solved! Go to Solution.
Hi @Anonymous
First select "Route Cost" columns and unpivot columns.
Create a measure
value 2100 belongs to customer b.
Best Regards
Maggie
Community Support Team _ Maggie Li
If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.
Hi @Anonymous
First select "Route Cost" columns and unpivot columns.
Create a measure
value 2100 belongs to customer b.
Best Regards
Maggie
Community Support Team _ Maggie Li
If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.
For the date, you should create a date dimension and join with your date and use the filter from date dimension
Customer if you create a dimension(Separate Table) it would better. Or you can use the filter from the same table
Measure like this should work
Measure =calculate(sum(Table[Route Cost A])+ sum(Table[Route Cost B])+ sum(Table[Route Cost C]))
Hi @amitchandak , thank you for your fast response.
I already have separate "Calendar" and "Customer" table in my model and tried your measure. But the problem is that when Customer A is selected, all rows of customer different than A will be removed. Therefore some of the cost for A will not be counted, and some cost not for A will be counted.
Can you please help me with another solution?
Starting December 3, join live sessions with database experts and the Fabric product team to learn just how easy it is to get started.
March 31 - April 2, 2025, in Las Vegas, Nevada. Use code MSCUST for a $150 discount! Early Bird pricing ends December 9th.
User | Count |
---|---|
94 | |
92 | |
83 | |
71 | |
49 |
User | Count |
---|---|
143 | |
120 | |
110 | |
59 | |
57 |