Resultado incorrecto al aplicar una función FORMAT a una función de Fecha

[Higinio]

Buenas tardes.

Soy nuevo en esta comunidad y agradecería me constestasen a al siguiente pregunta:

¿Porqué cuando aplico la siguiente función, me devuelve el valor 1?

Estoy intentado averiguar el nombre del mes anterios a una fecha:

Nombre_Mes = UPPER(FORMAT(MONTH('Medidas FIXING'[Hoy]= TODAY()), "mmmm"))

El resultado es ENERO 

Gracias.

[Ahmedx · Accepted solution]

Name_Month = UPPER(FORMAT(EOMONTH(TODAY(),-1), "mmmm"))

[Ahmedx]

If this post helps, then please consider accepting it as the solution to help other members find it faster, and give a big thumbs up.

[Ahmedx · Accepted solution]

Name_Month = UPPER(FORMAT(EOMONTH(TODAY(),-1), "mmmm"))

[Higinio]

Thank Ahmedx. Your solution is OK.

But, I wonder why the FORMAT function doesn't work only with the TODAY() function and I have to add the EOMONTH function to it.

Do you know the reason for this behavior?

[Ahmedx · Accepted solution]

to return the name of the month using the FORMAT function, you need the value to be like a date. and in order to get the name of the previous month,
 you need to return the date today back, and this can be done using the EOMONTH function

[Ahmedx]

Name_Month = UPPER(FORMAT(TODAY()), "mmmm"))

[Ahmedx]

yo need wirte like this

Nombre_Mes = UPPER(FORMAT(DATE(2023,MONTH('Medidas FIXING'[Hoy]= TODAY()),1), "mmmm"))

[Higinio]

Hello Ahmedx.

Thanks by your answer, but in my computer, the result of your version of this measure is "DECEMBER", and should be "FEBRUARY", taking in accoubt thas the mesure of Hoy is : Hoy = TODAY()

[Higinio]

Also the same problem for the Mesure:

Name_Month = UPPER(FORMAT(MONTH(TODAY()), "mmmm"))