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sagarsahoo_123's avatar
sagarsahoo_123
Helper IV
3 years ago
Solved

Request help to write Code for Consecutive months Lower Performer

Hello Team,

I have a requirement in Power BI. I have a table having Employee ID and each Employee having Work Hours information month wise.

I want to display the users who are having less than 6hours average work time for consecutive 3months based on the month selection in the slicer. Need your help to write the DAX formula to acheive this. One sample example is given below.

Emp IDWork TimeMonth
15Jan
28Jan
39Jan
14Feb
27Feb
36Feb
14Mar
24Mar
35Mar

In the above if you look at the work time value for Emploee ID 1 who is less than 6 hours for Jan, Feb and March months.

I need to display those employee ID with Work hours value for last 3 months. Any help would be highly appreciated.

 

Regards,

Sagar

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  • v-henryk-mstf's avatar
    v-henryk-mstf
    3 years ago

    Hi sagarsahoo_123 ,

     

    Try formula like below:

    avg_ =
VAR avg_ =
    AVERAGEX (
        FILTER ( ALL ( 'Table' ), 'Table'[Emp ID] = MAX ( 'Table'[Emp ID] ) ),
        CALCULATE ( SUM ( 'Table'[Work Time] ) )
    )
RETURN
    IF ( avg_ < 6, "Yes", "No" )

     

    If the problem is still not resolved, please provide detailed error information and let me know immediately. Looking forward to your reply.


    Best Regards,
    Henry


    If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.

2 Replies

  • v-henryk-mstf's avatar
    v-henryk-mstf
    Community Support
    3 years ago

    Hi sagarsahoo_123 ,

     

    Try formula like below:

    avg_ =
VAR avg_ =
    AVERAGEX (
        FILTER ( ALL ( 'Table' ), 'Table'[Emp ID] = MAX ( 'Table'[Emp ID] ) ),
        CALCULATE ( SUM ( 'Table'[Work Time] ) )
    )
RETURN
    IF ( avg_ < 6, "Yes", "No" )

     

    If the problem is still not resolved, please provide detailed error information and let me know immediately. Looking forward to your reply.


    Best Regards,
    Henry


    If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.