Forum Discussion

imy's avatar
imy
Helper I
6 years ago

Progress charts

Good evening,

 

I am trying to produce a chart that shows the progress in data for example, today i have 2 deted items, 3 to be deleted and 5 NOT to delete. I need to check periodically (lets say every week) and show the progress on the same items (or even more categories if they exist) by date. Is this possible?

 

Many thanks!

 

3 Replies

    • imy's avatar
      imy
      Helper I

      Dear parry2k,

       

      I have a column with 4 different categories : DELETE, YES, NO, Set for deletion and some blanks (wich I need to include). I need to represent this in a bar chart (probably clustered colums chart). This is simple. However, we do weekly check on this results and we need to represent how this 4 categories change through time. For example:

      Week 1: Deleted 35, YES 50, NO, 100, Blank 350 = TOTAL: 535

      Week 2: Deleted 100, YES 100, NO, 100, Blank 200 = TOTAL: 535

      And so on.

      Is this possible?

      I hope my question is clearer now.

       

      Regards,

      Imy

       

       

       

       

       

       

       

      • v-juanli-msft's avatar
        v-juanli-msft
        Community Support

        Hi imy 

        Assume you have tables

        Create a calculated column

         

        Column cate = IF([cate]=BLANK(),"Blank",[cate])

         

        Create measures

         

        count = CALCULATE(COUNT(Sheet3[id]),FILTER(ALLSELECTED(Sheet3),Sheet3[Column cate]=MAX(Sheet3[Column cate])))
        
        current week = CALCULATE([count],FILTER(Sheet3,WEEKNUM(Sheet3[date],2)=WEEKNUM(TODAY(),2)))
        
        Last week = CALCULATE([count],FILTER(Sheet3,DATEDIFF(Sheet3[date],TODAY(),WEEK)=1))
        
        change every week = [current week]-[Last week]
        

         

        Best Regards
        Maggie
        Community Support Team _ Maggie Li
        If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.