Forum Discussion
Power Query Challenge for you M Ninjas
- 9 years ago
How about:
List.Distinct(List.Union(Table.ToColumns(Tabel1)))
(This is the entire query code)
How about:
List.Distinct(List.Union(Table.ToColumns(Tabel1)))
(This is the entire query code)
- neurojelly8 years agoNew Member
Hi Marcel,
Could you also do?:
List.Distinct(Table.Schema(Table1)[Name])
Question about List.Union:
I understand that "The returned list contains all items in any input lists" and the Union is operating on the output of Table.ToColumns which returns a nested list of "columns of values". However since our values are all coming from the same table can't we just grab the table columns directly as in my first question above?
Closeing statement:
Almost every time I visit this site your solution is typically chosen as the answer. I understand what it would take to accomplish this and its impressive. Really great work. Thanks for all your posts clarifying the use of the M language on this forum.
- alecpeterson8 years agoNew Member
This is pretty awesome. Is it possible to transpose the list so that the column headers remain and we still get distinct values for each column?
- alecpeterson8 years agoNew Member
This is pretty awesome. Is it possible to transpose the list so that column headers remain and we still get distinct values for each column? Kind of like a transposed version of: List.Distinct(Table.ToColumns(Tabel1)) except only unique values.
Thank you sir,
Alec