Join us at FabCon Atlanta from March 16 - 20, 2026, for the ultimate Fabric, Power BI, AI and SQL community-led event. Save $200 with code FABCOMM.
Register now!The Power BI Data Visualization World Championships is back! Get ahead of the game and start preparing now! Learn more
I have a data table (see the attached) , I am trying to get a calculated column based on some condition
Condition( if all FeeType is Hourly for a particular project then for that project the result will be Hourly, if all is NoBilling then NoBilling else Fixed) but I am not getting the result.
Solved! Go to Solution.
Hi @arifulice09 ,
Create a column like this:-
Column_ =
var _hourly = COUNTROWS(FILTER('Table (3)','Table (3)'[Feetype] = "Hourly" && 'Table (3)'[projectid] = EARLIER('Table (3)'[projectid])))
var _nobill = COUNTROWS(FILTER('Table (3)','Table (3)'[Feetype] = "NoBilling" && 'Table (3)'[projectid] = EARLIER('Table (3)'[projectid])))
var _proj = COUNTROWS(FILTER('Table (3)','Table (3)'[projectid] = EARLIER('Table (3)'[projectid])))
return SWITCH(TRUE(),
_hourly = _proj ,"Hourly",
_nobill = _proj,"No Biling",
"Fixed")Output:-
Thanks,
Samarth
Best Regards,
Samarth
If this post helps, please consider accepting it as the solution to help the other members find it more quickly.
Appreciate your Kudos!!
Connect on Linkedin
Hi @arifulice09 ,
Create a column like this:-
Column_ =
var _hourly = COUNTROWS(FILTER('Table (3)','Table (3)'[Feetype] = "Hourly" && 'Table (3)'[projectid] = EARLIER('Table (3)'[projectid])))
var _nobill = COUNTROWS(FILTER('Table (3)','Table (3)'[Feetype] = "NoBilling" && 'Table (3)'[projectid] = EARLIER('Table (3)'[projectid])))
var _proj = COUNTROWS(FILTER('Table (3)','Table (3)'[projectid] = EARLIER('Table (3)'[projectid])))
return SWITCH(TRUE(),
_hourly = _proj ,"Hourly",
_nobill = _proj,"No Biling",
"Fixed")Output:-
Thanks,
Samarth
Best Regards,
Samarth
If this post helps, please consider accepting it as the solution to help the other members find it more quickly.
Appreciate your Kudos!!
Connect on Linkedin
Hello there @arifulice09 ! Check if this works for you:
Desired Result =
SWITCH (
TRUE (),
DISTINCTCOUNT ( 'Table'[Feetype] ) > 1, "Fixed",
SELECTEDVALUE ( 'Table'[Feetype] )
)Hope this answer solves your problem!
If you need any additional help please @ me in your reply.
If my reply provided you with a solution, please consider marking it as a solution ✔️ or giving it a kudoe 👍
Thanks!
You can also check out my LinkedIn!
Best regards,
Gonçalo Geraldes
@goncalogeraldes Thanks for your reply, using the above code only giving the result of "Fixed" value.
The Power BI Data Visualization World Championships is back! Get ahead of the game and start preparing now!
| User | Count |
|---|---|
| 39 | |
| 37 | |
| 33 | |
| 32 | |
| 29 |
| User | Count |
|---|---|
| 133 | |
| 88 | |
| 85 | |
| 68 | |
| 64 |