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Anonymous
Not applicable

## Percentage values of of a column instead of grand total

I would like to get a % of each month to sum up to 100% instead of grand total.

What I have now:

When I change from numbers to % I have like this:

But I would like to have like this:

How can I get to this?

1 ACCEPTED SOLUTION
Super User

@Anonymous ,

You want overall %

divide([measure], calculate([measure], allselected())

or

for legend column

divide([measure], calculate([measure], filter(allselected(Table), Table[Legend column] = max(Table[Legend column] ))))

or

for legend month year

divide([measure], calculate([measure], filter(allselected(Table), Table[month year] = max(Table[month year] ))))

2 REPLIES 2
Super User

@Anonymous ,

You want overall %

divide([measure], calculate([measure], allselected())

or

for legend column

divide([measure], calculate([measure], filter(allselected(Table), Table[Legend column] = max(Table[Legend column] ))))

or

for legend month year

divide([measure], calculate([measure], filter(allselected(Table), Table[month year] = max(Table[month year] ))))

Anonymous
Not applicable

Thank you, it's working!

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