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DriesD's avatar
DriesD
Regular Visitor
6 years ago
Solved

Order count - Benchmark against Employee count

Hello everyone,

First post here on the forum, relatively new to PowerBi, getting out of the basics and navigation and now struggling with some more 'complex' calculations where I cannot seem to find an answer in the many youtube videos or existing posts here. 


If anyone would be able to help with this, that would be great

I can easily count the total of orders per company code, in my easy date example below US1 - 3 and CA1 also 3.

next to this total I want to divide that total number by the amount of technicians per company code. this amount I have manually put in a separate table, put I cannot seem to do this with a DIVIDE or CALCULATE function...

(as dividing by the amount of technicians basically benchmarks the countries better)

Company CodeOrdernumberCreated On
US110011/5/2020
US110021/13/2020
US110031/7/2020
CA110041/8/2020
CA110051/10/2020
CA110061/10/2020

 

Second table

Company CodeTechnicians
US110
CA15

 

Further down in my report I want to do the same thing, where I'm not looking at totals, but I'm looking at orders created per day, totals. Also this graph I would like to bring down to a level of orders created per day, divided by the amount of technicians.

  • Hi DriesD 

    With relationships and measure below, we could get the result easily.

    total = DISTINCTCOUNT(Table1[Ordernumber])
    
    average = [total]/SUM(Table2[Technicians])

    But for the next question, total per day/ technicians, i don't know what technicians should be used.

    Could you give me an example?

    Best Regards
    Maggie
    Community Support Team _ Maggie Li
    If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.

5 Replies

  • DriesD  You need to create a relationship between the two tables on the Company Code column.

     

    Then, create a calculated column in your Order table as follows:

    Technicians = RELATED(CompanyCodesTable[Technicians])
     
    Then create your measure that will provide you the orders per technician for each company.
    Orders per Technician = DIVIDE(DISTINCTCOUNT(OrderTable[Ordernumber]), AVERAGE(OrderTable[Technicians]))
     
    This measure will work if you drop it into a table where you put the conpany code from the company codes table.
     
    A picture below shows how it will look. For the date, you will need to create a calendar column first and go from there.

     
     
  • v-juanli-msft's avatar
    v-juanli-msft
    Community Support

    Hi DriesD 

    With relationships and measure below, we could get the result easily.

    total = DISTINCTCOUNT(Table1[Ordernumber])
    
    average = [total]/SUM(Table2[Technicians])

    But for the next question, total per day/ technicians, i don't know what technicians should be used.

    Could you give me an example?

    Best Regards
    Maggie
    Community Support Team _ Maggie Li
    If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.
    • DriesD's avatar
      DriesD
      Regular Visitor

      hi Maggie, it's basically the same. 
      I'm trying to look at all orders created per company code, which you have shown in your example. Per day is the same thing, the total amount of orders created per day, per technician 

      (so total order count created on that day, divided by total amount of technicians)
      thanks for your reply, I will look into this and revert back!

      • v-juanli-msft's avatar
        v-juanli-msft
        Community Support

        Hi DriesD 

        As i checked, my reply covers the above you concern.

        If there is still any problem, please tell me.

         

        Best Regards
        Maggie
        Community Support Team _ Maggie Li
        If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.

  • DriesD's avatar
    DriesD
    Regular Visitor

    oh wow, such great and quick responses, thank you all! 

     

    I will check the answers and provide feedback throughout the day/tomorrow!