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PBI_User1
New Member

Measure doesn't work as expected

Hi, I'm trying to create a Measure to do an incremental sum.

Cost running total in Date =
CALCULATE(
SUM('JobDocs'[Cost]);
FILTER(
ALLSELECTED('JobDocs'[Date]);
ISONORAFTER('JobDocs'[Date]; MAX('JobDocs'[Date]); DESC)
)
)


Somebody can help me?

Thanks


pbi_data.png

 

1 ACCEPTED SOLUTION
v-jiascu-msft
Microsoft Employee
Microsoft Employee

Hi @PBI_User1,

 

Try this formula please.

 

Cost running total in Date =
CALCULATE (
    SUM ( 'JobDocs'[Cost] );
    FILTER ( ALL ( 'JobDocs' ); 'JobDocs'[Date] <= MAX ( 'JobDocs'[Date] ) )
)

Best Regards,

Dale

 

Community Support Team _ Dale
If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.

View solution in original post

3 REPLIES 3
Ashish_Mathur
Super User
Super User

Hi,

 

Try this measure

 

=CALCULATE(SUM('JobDocs'[Cost]),DATESYTD(Calendar[Date],"31/12/"))

 

Here are the assumptions:

 

  1. You have a calendar Table with Month and Year columns
  2. There is a relationship from the Data column of the JobsDocs Table to the Date column of the Calendar Table
  3. In your visual, you will drag Year and Month from the Calendar Table.

Hope this helps.


Regards,
Ashish Mathur
http://www.ashishmathur.com
https://www.linkedin.com/in/excelenthusiasts/
v-jiascu-msft
Microsoft Employee
Microsoft Employee

Hi @PBI_User1,

 

Could you please mark the answer as a solution or share your solution?

 

Best Regards,

Dale

Community Support Team _ Dale
If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.
v-jiascu-msft
Microsoft Employee
Microsoft Employee

Hi @PBI_User1,

 

Try this formula please.

 

Cost running total in Date =
CALCULATE (
    SUM ( 'JobDocs'[Cost] );
    FILTER ( ALL ( 'JobDocs' ); 'JobDocs'[Date] <= MAX ( 'JobDocs'[Date] ) )
)

Best Regards,

Dale

 

Community Support Team _ Dale
If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.

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