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ScottGunsaullus
Frequent Visitor

Measure compares client's value to most recent previous value (improved, not improved, same)

Sample data:

PHQ9_sample.png

For each row and client [PATID], I need to calculate 3 things: 

  1. Was there a previous [total_score] and if so,
  2. What was the previous [total_score]?
  3. What was the difference between the [total_score] and the previous [total_score]?

Zero is a valid score.  Lower scores are better.  So, a negative difference would indicate improvement.

PHQ9_sample2.png

 

 

 

2 ACCEPTED SOLUTIONS
Selva-Salimi
Super User
Super User

Hi @ScottGunsaullus 

 

you can write these 3 columns :

 

Prev_assessment = if (calculate(max('Your_table'[assessment_date]) , FILTER('Your_table' , 'Your_table'[PATID]=EARLIER('Your_table'[PATID]) && 'Your_table'[assessment_date] < EARLIER('Your_table'[assessment_date]))) <> Blank() , "Yes" , "No")
 
Prev_total_score =
var prev_date = calculate(max('Your_table'[assessment_date]) , FILTER('Your_table' , 'Your_table'[PATID]=EARLIER('Your_table'[PATID]) && 'Your_table'[assessment_date] < EARLIER('Your_table'[assessment_date])))
return
CALCULATE(max('Your_table'[total_score]) , filter('Your_table','Your_table'[assessment_date] = prev_date
&& Your_table[PATID]=EARLIER(Your_table[PATID])
))
 
difference = 'Your_table'[total_score] - 'Your_table'[Prev_total_score]
 
If this post helps, then I would appreciate a thumbs up 👍 and mark it as the solution to help the other members find it more quickly.
 

 

View solution in original post

@Selva-Salimi 

I had to make a minor change to the second column. CALCULATE needs to consider both PATID and assessment_date.

I could not have solved this without your help.  Thanks again,

 

Prev_total_score =
var prev_date = calculate(max('Your_table'[assessment_date]) , FILTER('Your_table' , 'Your_table'[PATID]=EARLIER('Your_table'[PATID]) && 'Your_table'[assessment_date] < EARLIER('Your_table'[assessment_date])))
return
CALCULATE(max('Your_table'[total_score]) , ALLEXCEPT ( 'Your_table', 'Your_table'[PATID]), 'Your_table'[assessment_date] = prev_date)

View solution in original post

3 REPLIES 3
Selva-Salimi
Super User
Super User

Hi @ScottGunsaullus 

 

you can write these 3 columns :

 

Prev_assessment = if (calculate(max('Your_table'[assessment_date]) , FILTER('Your_table' , 'Your_table'[PATID]=EARLIER('Your_table'[PATID]) && 'Your_table'[assessment_date] < EARLIER('Your_table'[assessment_date]))) <> Blank() , "Yes" , "No")
 
Prev_total_score =
var prev_date = calculate(max('Your_table'[assessment_date]) , FILTER('Your_table' , 'Your_table'[PATID]=EARLIER('Your_table'[PATID]) && 'Your_table'[assessment_date] < EARLIER('Your_table'[assessment_date])))
return
CALCULATE(max('Your_table'[total_score]) , filter('Your_table','Your_table'[assessment_date] = prev_date
&& Your_table[PATID]=EARLIER(Your_table[PATID])
))
 
difference = 'Your_table'[total_score] - 'Your_table'[Prev_total_score]
 
If this post helps, then I would appreciate a thumbs up 👍 and mark it as the solution to help the other members find it more quickly.
 

 

@Selva-Salimi 

I had to make a minor change to the second column. CALCULATE needs to consider both PATID and assessment_date.

I could not have solved this without your help.  Thanks again,

 

Prev_total_score =
var prev_date = calculate(max('Your_table'[assessment_date]) , FILTER('Your_table' , 'Your_table'[PATID]=EARLIER('Your_table'[PATID]) && 'Your_table'[assessment_date] < EARLIER('Your_table'[assessment_date])))
return
CALCULATE(max('Your_table'[total_score]) , ALLEXCEPT ( 'Your_table', 'Your_table'[PATID]), 'Your_table'[assessment_date] = prev_date)

@ScottGunsaullus 

 

thanks to pointing that out. you are right, one filter was missed. I have updated my previous response. I would appriciate to mark it as solution to help others find it quickly.

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