Inspection Dataset Measures

[Anonymous]

I have an inspection dataset similar to the below.

ID	Date	Result
1	01/01/2022	Pass
1	02/01/2022	Fail
2	01/01/2022	Pass
2	02/01/2022	Pass
2	03/01/2022	Fail

I want to create a measure which can track the following:

1. Looking at individual ID's, I want to track the average time it takes to Fail after recieving a Pass as the first result
   
   
2. Count of distinct ID's that only ever recieve a Pass
3. Count of distinct ID's that recieve a Pass as their first result then a Fail any time after the first Pass

Many thanks 🙂 

[v-kkf-msft]

Hi @Anonymous ,

Please try the following formula:

Datediff = 
VAR startdate =
    CALCULATE ( MIN ( 'Table'[Date] ), 'Table'[Result] = "Pass" )
VAR enddate =
    CALCULATE (
        MIN ( 'Table'[Date] ),
        'Table'[Result] = "Fail",
        'Table'[Date] >= startdate
    )
RETURN
    DATEDIFF ( startdate, enddate, DAY )

Average time = AVERAGEX ( VALUES ( 'Table'[ID] ), [Datediff] )

CountResultPerID = 
CALCULATE (
    DISTINCTCOUNT ( 'Table'[Result] ),
    ALLEXCEPT ( 'Table', 'Table'[ID] )
)

only recieve Pass = 
CALCULATE (
    DISTINCTCOUNT ( 'Table'[ID] ),
    FILTER ( 'Table', 'Table'[Result] = "Pass" && [CountResultPerID] = 1 )
)

recieve Pass then Fail =
VAR Firstday =
    CALCULATE ( MIN ( 'Table'[Date] ), ALLEXCEPT ( 'Table', 'Table'[ID] ) )
RETURN
    CALCULATE (
        DISTINCTCOUNT ( 'Table'[ID] ),
        FILTER (
            'Table',
            'Table'[Date] = Firstday
                && 'Table'[Result] = "Pass"
                && [CountResultPerID] = 2
        )
    )

If the problem is still not resolved, please provide detailed error information or the expected result you expect. Let me know immediately, looking forward to your reply.
Best Regards,
Winniz
If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.

[Anonymous]

Hi,

Thanks for your response. I have added all measures into my PBIX file and are recieving some errors.

Looking at ID 1796 in particalar I have the below data.

ID	Date	Result
1796	15/12/2021	Pass
1796	08/12/2021	Pass
1796	01/12/2021	Pass
1796	24/11/2021	Pass
1796	17/11/2021	Pass
1796	10/11/2021	Pass
1796	03/11/2021	Pass
1796	27/10/2021	Pass
1796	20/10/2021	Pass
1796	13/10/2021	Pass
1796	06/10/2021	Pass
1796	29/09/2021	Pass
1796	22/09/2021	Pass
1796	15/09/2021	Pass
1796	08/09/2021	Pass
1796	01/09/2021	Pass
1796	25/08/2021	Fail

I am seeing the below results which is not correct as this specific ID has a fail.

Any ideas?

[v-kkf-msft · Accepted solution]

Hi @Anonymous ,

I modify these measures, please try them:

Datediff = 
VAR startdate =
    CALCULATE ( MIN ( 'Table'[Date] ), 'Table'[Result] = "Pass" )
VAR enddate =
    CALCULATE (
        MIN ( 'Table'[Date] ),
        'Table'[Result] = "Fail",
        'Table'[Date] >= startdate
    )
RETURN
    DATEDIFF ( startdate, enddate, DAY ) + 0

Total recieve Pass then Fail = SUMX ( VALUES ( 'Table'[ID] ), [recieve Pass then Fail] )

If the problem is still not resolved, please provide detailed error information or the expected result you expect. Let me know immediately, looking forward to your reply.
Best Regards,
Winniz
If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.

[lbendlin]

Please provide sanitized sample data that fully covers your issue. Your scenario 2 is not covered.

Please show the expected outcome based on the sample data you provided.

[Anonymous]

Hi,

Thanks for your response. Unfortunetely due to company confidentity I can only supply a sample dataset.

ID	Date	Result
1	01/01/2022	Pass
1	02/01/2022	Fail
2	01/01/2022	Pass
2	02/01/2022	Pass
2	03/01/2022	Fail
3	01/02/2022	Pass

Based upon the above dataset I would see the below outcomes for each scenario.

1. Average time it takes to fail after recieving a pass as the first result = 1.5 days

2. Count of distinct ID's that only ever recieve a Pass = 1 

3. Count of distinct ID's that recieve a Pass as their first result then a Fail any time after the first Pass = 2

Hope this helps.