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maheshbabu
Frequent Visitor

How to sort a bar chart or clustered bar chart with two or more measures?

Hi, I am working on HR Attrition dashboard. My requirement is to build visuals which show highest attrition by supervisor in that organisation. Now, management came up with new requirement as the visual must be sorted by attrition and headcount of that supervisor. They are asking sort by highest headcount and highest attrition. How can we do sort by two measures as each supervisor has different heacounts and attriters. If any one knows, please let me know.I have applied top N filter by headcount and sorted it with attriters. But its not interactive.I have applied top N filter by headcount and sorted it with attriters. But its not interactive.

1 ACCEPTED SOLUTION
Anonymous
Not applicable

Hi @maheshbabu ,

 

You can first calculate the ranking of heacounts and attriters separately.

rank by heacounts = RANKX(ALL('Table'),[heacounts measure],,DESC,Dense)
rank by attriters = RANKX(ALL('Table'),[attriters measure],,DESC,Dense)

Then there will be a priority selection, here I choose ‘attriters’ to have a higher priority than 'heacounts'.

 

rank by attriters and heacounts = RANKX(ALL('Table'),[rank by attriters]*100+[rank by heacounts],,ASC,Dense)

vstephenmsft_0-1653892219765.png

 

 

Best Regards,

Stephen Tao

 

If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.

 

View solution in original post

2 REPLIES 2
maheshbabu
Frequent Visitor

Thanks a lot

Anonymous
Not applicable

Hi @maheshbabu ,

 

You can first calculate the ranking of heacounts and attriters separately.

rank by heacounts = RANKX(ALL('Table'),[heacounts measure],,DESC,Dense)
rank by attriters = RANKX(ALL('Table'),[attriters measure],,DESC,Dense)

Then there will be a priority selection, here I choose ‘attriters’ to have a higher priority than 'heacounts'.

 

rank by attriters and heacounts = RANKX(ALL('Table'),[rank by attriters]*100+[rank by heacounts],,ASC,Dense)

vstephenmsft_0-1653892219765.png

 

 

Best Regards,

Stephen Tao

 

If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.

 

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