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ckwongak
Frequent Visitor

How to return table based on condition with DAX?

Hi all,

 

I have two slicer, one slicer contains the full name of country (for e.g. Japan), one table contains the mapping of the currency for that country and one table contains only one row "USD" as the currency

 

I want to have one slicer with options below:

 

If one country is selected, I will show two currency (e.g. if japan is selected, I will show JPY, USD)

If more than one country is selected, I will always show USD 

 

How to do this in Power BI?

 

1 ACCEPTED SOLUTION
v-rzhou-msft
Community Support
Community Support

Hi @ckwongak ,

 

My Sample is as below.

Currency:

vrzhoumsft_0-1682578049940.png

DimCountry:

vrzhoumsft_1-1682578060471.png

Table:

vrzhoumsft_2-1682578066749.png

Data model:

vrzhoumsft_3-1682578109438.png

Measure:

Currency Appear when only one country is selected = 
VAR _SELECTVALUE =
    SELECTEDVALUE ( 'Currency'[Currency] )
VAR _COUNT =
    COUNTAX ( VALUES ( DimCountry[Country] ), [Country] )
RETURN
    IF ( _COUNT = 1, CALCULATE ( SUM ( 'Table'[USD] ) ) * _SELECTVALUE )

Result is as below.

vrzhoumsft_4-1682578146669.png

vrzhoumsft_5-1682578154555.png

 

Best Regards,
Rico Zhou

 

If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.

 

View solution in original post

1 REPLY 1
v-rzhou-msft
Community Support
Community Support

Hi @ckwongak ,

 

My Sample is as below.

Currency:

vrzhoumsft_0-1682578049940.png

DimCountry:

vrzhoumsft_1-1682578060471.png

Table:

vrzhoumsft_2-1682578066749.png

Data model:

vrzhoumsft_3-1682578109438.png

Measure:

Currency Appear when only one country is selected = 
VAR _SELECTVALUE =
    SELECTEDVALUE ( 'Currency'[Currency] )
VAR _COUNT =
    COUNTAX ( VALUES ( DimCountry[Country] ), [Country] )
RETURN
    IF ( _COUNT = 1, CALCULATE ( SUM ( 'Table'[USD] ) ) * _SELECTVALUE )

Result is as below.

vrzhoumsft_4-1682578146669.png

vrzhoumsft_5-1682578154555.png

 

Best Regards,
Rico Zhou

 

If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.

 

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