Forum Discussion
Anonymous
4 years agoNot applicable
How to find repetitive values
Hi,
I am trying to create a measure that can limit the number of hang up calls. Sth. like this:
if a Calling Party Nr repeates more than 5 times a day, set the # of hang up calls to 5, else set the current number.
How can I do that?
Thanks!
Hi Anonymous ,
Pls test the below:
test = VAR test1 = CALCULATE ( SUM ( 'Table'[# of hang up calls] ), FILTER ( ALL ( 'Table' ), 'Table'[Date] = MAX ( 'Table'[Date] ) && 'Table'[Calling Party NR] = MAX ( 'Table'[Calling Party NR] ) ) ) RETURN IF ( test1 >= 5, 5, MAX ( 'Table'[Calling Party NR] ) )Output result:
Did I answer your question? Mark my post as a solution!
Best RegardsLucien
3 Replies
- johncolley
Solution Sage
Hi Anonymous ,
Create the following measures:
Hang up calls = SUM('Table'[# of Hang up calls])
limitto5 = SWITCH(
TRUE(),
[Hang up calls] > 5, 5,
[Hang up calls] <=5, [Hang up calls]
)If this solution solved your problem, please mark it as a solution!
- danextian
Super User
Hi Anonymous
These measure below will count the number of hang up calls per number per date regardless of the filter context.
Count of Hang Up Calls per Nr and Date = CALCULATE ( COUNTROWS ( Table ), ALLEXCEPT ( Table, Table[Date], Table[Calling Party Nr] ) ) - v-luwang-msft
Community Support
Hi Anonymous ,
Pls test the below:
test = VAR test1 = CALCULATE ( SUM ( 'Table'[# of hang up calls] ), FILTER ( ALL ( 'Table' ), 'Table'[Date] = MAX ( 'Table'[Date] ) && 'Table'[Calling Party NR] = MAX ( 'Table'[Calling Party NR] ) ) ) RETURN IF ( test1 >= 5, 5, MAX ( 'Table'[Calling Party NR] ) )Output result:
Did I answer your question? Mark my post as a solution!
Best RegardsLucien