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Greetings
I have 2 colums with lists like so:
Each list contains several values, each of which corresponds to a value in the same position within the second list. Like so:
Column 1 | Column 2
[1,2,3,4,5] | [A,B,C,D,E]
If I expand the first column and than the second column I will end up with a value pair for each element:
Column 1 | Column 2
1 A
1 B
1 C
1 D
1 E
2 A
2 B
... ...
However I want to end end up with this:
Column 1 | Column 2
1 A
2 B
3 C
4 D
5 E
Does anyone has any idea how could I solve this problem?
Thanks
Zaza
Solved! Go to Solution.
@zaza , try this M code:
et <PreviousStep> = some table, Add_Zipped = Table.AddColumn(<PreviousStep>, "Zipped", each List.Zip({[Column1], [Column2]}), type list), Expand_Zipped = Table.ExpandListColumn(Add_Zipped, "Zipped"), Extract_Zipped = Table.TransformColumns(Expand_Zipped, {"Zipped", each Text.Combine(List.Transform(_, Text.From), ";"), type text}), Split_Column = Table.SplitColumn(Extract_Zipped, "Zipped", Splitter.SplitTextByEachDelimiter({";"}, QuoteStyle.Csv, false), {"Zipped.1", "Zipped.2"}) in Split_Column
List.Zip() will combine the 2 lists into nested lists of {1, A}, {2, B}, {3, C}, etc.
You expand that to get 5 rows, each row will have 1 of these lists.
You extract the values and add a semicolon between values to delimit.
Then split the column by the semicolon delimiter.
Hope this helps!
~ Chris
@zaza , try this M code:
et <PreviousStep> = some table, Add_Zipped = Table.AddColumn(<PreviousStep>, "Zipped", each List.Zip({[Column1], [Column2]}), type list), Expand_Zipped = Table.ExpandListColumn(Add_Zipped, "Zipped"), Extract_Zipped = Table.TransformColumns(Expand_Zipped, {"Zipped", each Text.Combine(List.Transform(_, Text.From), ";"), type text}), Split_Column = Table.SplitColumn(Extract_Zipped, "Zipped", Splitter.SplitTextByEachDelimiter({";"}, QuoteStyle.Csv, false), {"Zipped.1", "Zipped.2"}) in Split_Column
List.Zip() will combine the 2 lists into nested lists of {1, A}, {2, B}, {3, C}, etc.
You expand that to get 5 rows, each row will have 1 of these lists.
You extract the values and add a semicolon between values to delimit.
Then split the column by the semicolon delimiter.
Hope this helps!
~ Chris
@Anonymous thank you for the solution, it works perfectly!
March 31 - April 2, 2025, in Las Vegas, Nevada. Use code MSCUST for a $150 discount! Early Bird pricing ends December 9th.
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