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Jia_Shi's avatar
Jia_Shi
New Member
3 years ago
Solved

How to create a dynamic column chart with time filter

Hi all,

I am inquiring about how to create a column graph that displays data for the last 24 months, with the ability to select a specific month and have the graph adjust to display data for the selected month and 23 months before.

For example, if today is May 2023, the graph would display data from June 2021 to May 2023 by default. However, if you selected January 2023 in the time slicer, the graph would adjust to display data from February 2021 to January 2023.

 

Additionally, I have included a rolling 12-month line trend to the column chart, and I would like to make it also dynamically adjustable.

 

Thank you in adevance!

  • Anonymous's avatar
    Anonymous
    3 years ago

    Hi Jia_Shi 

    You can try to use EOMONTH() function.

    e.g 

     

    Measure =
    CALCULATE (
        SUM ( 'Table'[Sales] ),
        FILTER (
            'Table',
            [Date]
                >= EOMONTH ( SELECTEDVALUE ( 'Table'[Date] ), -14 ) + 1
                && [Date] < SELECTEDVALUE ( 'Table'[Date] )
        )
    )
    

     

    You can refer to the following link to know more about this function.

    EOMONTH function - Microsoft Support

     

    Best Regards!

    Yolo Zhu

    If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.

2 Replies

  • Anonymous's avatar
    Anonymous
    Not applicable

    Hi Jia_Shi 

    You can try to use EOMONTH() function.

    e.g 

     

    Measure =
    CALCULATE (
        SUM ( 'Table'[Sales] ),
        FILTER (
            'Table',
            [Date]
                >= EOMONTH ( SELECTEDVALUE ( 'Table'[Date] ), -14 ) + 1
                && [Date] < SELECTEDVALUE ( 'Table'[Date] )
        )
    )
    

     

    You can refer to the following link to know more about this function.

    EOMONTH function - Microsoft Support

     

    Best Regards!

    Yolo Zhu

    If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.