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I have a formula like this:
Solved! Go to Solution.
Short answer: as VALUES(tablename[columnname]) gives you a single column table of distinct values, you can use either COUNTROWS(VALUES(tablename[columnname])) or DISTINCTCOUNT(tablename[columnname])
I wonder what the bigger picture is here, like I wonder if that filter will work.
Short answer: as VALUES(tablename[columnname]) gives you a single column table of distinct values, you can use either COUNTROWS(VALUES(tablename[columnname])) or DISTINCTCOUNT(tablename[columnname])
I wonder what the bigger picture is here, like I wonder if that filter will work.
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