Forum Discussion
Have distinct result after filter
Hello,
Is it possible to have distinct result after filter.
Here my case :
I have an columne "Client Name" and i want to know the number of intervention that they had (with my colomne DateIntervention) in one years so i used the relative date filter i succeeded to have an result but i want to have distinct result with the colomne name. how can i do that ?
I hope i was clear, i know my english is not that perfect, sorry for that.
if someone can help me , if you need more informations guys tell me.
Thanks for the futur answer.
Hi ItSupportElm
You can create a measure to count the rows for each id.
Measure = COUNT('Table'[dateintervention])Best Regards
MaggieCommunity Support Team _ Maggie Li
If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.
6 Replies
- v-juanli-msft
Community Support
Hi ItSupportElm
As tested, i have distinct values on my table chart.
Could you show screenshots to help me understand better about your scenario?
Best Regards
MaggieCommunity Support Team _ Maggie Li
If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.- ItSupportElm
Helper III
thank you for your answer v-juanli-msft
Actually he didnt work for me, i think because DateIntervention is in differente Table that ClientName who is an differente table too.
Do you have an solution for me, formule i can use or a trick to do ?
(I precise that i pick my data on database MySql server)
You can see on the screenshot for exemple there 3 times Idclient : 6 , i just want to have one , i dont care about the dateintervention they keep.
- v-juanli-msft
Community Support
Hi ItSupportElm
To get distinct client name, you could summarize the "dateinterview" column by selecting "earliest" or "last" or "count".
Best Regards
MaggieCommunity Support Team _ Maggie Li
If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.
- v-juanli-msft
Community Support
Hi ItSupportElm
Is this problem sloved?If it is sloved, could you kindly accept it as a solution to close this case?If not, please let me know.Best RegardsMaggie