Get latest record by ID

[Jabz]

Hi, i am trying to get the last record by ID but it has to work with date filters, for example, i have the following table:

ID       Date      

A        1 Jan

A        10 Jan

B        29 Jan 

B        16 Feb

A        1 Feb

B         20 Feb

So, if i filter the table by January it will show me only the A record with date 10 Jan and B record with date 29 Jan, and if i filter by February it will show A record with Date 1 Feb and B record with Date 20 Feb.

Is there a way to do this in a measure? because i searched for solutions but the majority of them just use a calculate column to get the max date but that doesn´t work in my case since i want to filter "dynamically".

Basically i need that whatever date filter is, show me the last record by ID in that date.

[AlexisOlson · Accepted solution]

There are several ways to do this. See for example my post here from 2018:
https://stackoverflow.com/questions/52525377/return-top-value-ordered-by-another-column

I'd recommend using the INDEX function.

CALCULATE ( 
    [Your Measure Here],
    INDEX ( 1, ORDERBY ( Table1[Date] ), DESC ),
    PARTITIONBY ( Table1[ID] )
)

[v-xuxinyi-msft · Accepted solution]

Hi @Jabz 

Here is my testing.

Date table:

Mesure:

Measure = 
VAR _MaxDate = CALCULATE(MAX([Date]), FILTER(ALLEXCEPT('Table','Table'[ID]), MONTH([Date]) = MONTH(SELECTEDVALUE('Date'[Date]))))
RETURN
IF(MAX([Date]) = _MaxDate, 1, 0)

Put the measure into the filter so that the visual only shows data where the measure is equal to 1.

Filter with Date table

Is this the result you expect?

Best Regards,
Yulia Xu

If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.

[AlexisOlson · Accepted solution]

There are several ways to do this. See for example my post here from 2018:
https://stackoverflow.com/questions/52525377/return-top-value-ordered-by-another-column

I'd recommend using the INDEX function.

CALCULATE ( 
    [Your Measure Here],
    INDEX ( 1, ORDERBY ( Table1[Date] ), DESC ),
    PARTITIONBY ( Table1[ID] )
)