cancel
Showing results for
Did you mean:

Find everything you need to get certified on Fabric—skills challenges, live sessions, exam prep, role guidance, and more. Get started

Helper III

## Get data from another column and function earlier

I have a table like the following one in which I use the earlier function to calculate the sum of each product, but now I have another table in which I have a percentage, and this value I need to multiply by each row of the sum column, how can I get That value being that I am already using the function earlier and such that it matches the Store and Product column?

sum = calculate (sum ('A' [price])) , FILTER ('A', [index] <= EARLIER ('A' [index]) && [store] = EARLIER ('A' [store]) ))

 index Store Year Month Product price sum 1 1 2021 1 A 8000 8000 2 1 2021 2 B 1000 9000 3 1 2021 3 C 5000 14000

Other table

 Store Product Percentage 1 A 0.9 1 B 0.5 1 C 0.3
1 ACCEPTED SOLUTION
Community Support

Hi, @nicolasvc

You can try the following methods:

1. I have prepared tables a and B first. Sum is the calculation column.

2. Use the LOOKUPVALUE function to match the sum column of table A to table B.

Sum =
LOOKUPVALUE ( A[Sum], A[ Store], [Store], A[ Product], [ Product] )

3. The value you want is shown in the figure:

Value = B[Sum]*B[ Percentage]

If the method I provided above can't solve your problem, what's your expected result? Could you please provide more details for it?

Best Regards,

Charlotte Zhang

If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.

2 REPLIES 2
Community Support

Hi, @nicolasvc

You can try the following methods:

1. I have prepared tables a and B first. Sum is the calculation column.

2. Use the LOOKUPVALUE function to match the sum column of table A to table B.

Sum =
LOOKUPVALUE ( A[Sum], A[ Store], [Store], A[ Product], [ Product] )

3. The value you want is shown in the figure:

Value = B[Sum]*B[ Percentage]

If the method I provided above can't solve your problem, what's your expected result? Could you please provide more details for it?

Best Regards,

Charlotte Zhang

If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.

Super User

@nicolasvc , Use MAxx if needed

% = sumX (FILTER ('B', 'A'[index] <= ('B' [index]) && 'A'[store] = ('B' [store]) ), 'B' [Percentage])

or

% = MAXX(FILTER ('B', 'A'[index] <= ('B' [index]) && 'A'[store] = ('B' [store]) ), 'B' [Percentage])

refer 4 ways to copy data from one table to another

Announcements

#### Europe’s largest Microsoft Fabric Community Conference

Join the community in Stockholm for expert Microsoft Fabric learning including a very exciting keynote from Arun Ulag, Corporate Vice President, Azure Data.