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NavaneethaRaju
Helper IV
Helper IV

Find the count of IF condition returned 1 and have to find the late return %

Hi ,

I have column called late return its having the diffrence between two dates, and after that i write the IF condition to show the correct return Fl and late return Fl , there im showing the one and Zeros for that condition. I want to count the how many 1's are there in two columns. I have to find the difference %.

%= 15/(15+6)=71%

 

NavaneethaRaju_0-1666101594864.png

Please advice me to create calculated column and measure for thiss.

1 ACCEPTED SOLUTION
mangaus1111
Solution Sage
Solution Sage

Hi @NavaneethaRaju ,

 

to calculate the Pct of Late Return, you just need a simple measure like this:

 

Pct Late Return= DIVIDE(
                  CALCULATE(
                           COUNT(Table[Late Return]),
                            Table[Late Return]>0
                            ),
                 COUNTROWS('Table')
)
 
If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.

View solution in original post

1 REPLY 1
mangaus1111
Solution Sage
Solution Sage

Hi @NavaneethaRaju ,

 

to calculate the Pct of Late Return, you just need a simple measure like this:

 

Pct Late Return= DIVIDE(
                  CALCULATE(
                           COUNT(Table[Late Return]),
                            Table[Late Return]>0
                            ),
                 COUNTROWS('Table')
)
 
If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.

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