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Thor2022's avatar
Thor2022
Frequent Visitor
3 years ago
Solved

Filter the contents inside MATRIX visual

Dear All  I have a matric that contains the following information:  - Rows: Warehouse names: A, B and C  - Columns: Years  - Values: Profits    and I have a multiselection slicer that contains ...
Tips and Tricks
  • PaulDBrown's avatar
    PaulDBrown
    3 years ago

    Thor2022 

    Actually, thinking about it, the average method could potentially not achieve what you are looking for.

    If you have a set of values for a year like {30, 29, 30, 31}, the average method will hide both 30 values.

    The following  method however will work: compare the minimum value in a set to the maximum value. If they are the same, all values are the same...

    So...

     

    No duplicate profits =
VAR _Min =
    MINX ( ALL ( 'Warehouse table'[Warehouse] ), [Your measure] )
VAR _MAX =
    MAXX ( ALL ( 'Warehouse table'[Warehouse] ), [Your measure] )
RETURN
    IF (
        AND (
            ISINSCOPE ( 'Warehouse table'[Warehouse] ),
            ISINSCOPE ( 'Year Table'[Year] )
        ),
        IF ( _Min = _Max, BLANK (), [Your measure] )
    )

     

     

    PS. I tried deleting the previous message but the forum won't let me for that particular post for some reason....

     

     

pi_eye's avatar
pi_eye
Resolver IV
3 years ago

Hi Thor

 

Can you elaborate on the example? So for example if the column values for year #2 are 5,6 and 7, it shows but if it is 3,3, and 3  it is blank?

 

See example below:

 

Try this expresion in DAX:

Show diff Values = If(Calculate(DISTINCTCOUNT(WareHouse[Value]),ALLSELECTED(WareHouse[WareHouse]))=1,"", Sum(WareHouse[Value]))

 

What it is doing:

Calculate(DISTINCTCOUNT(WareHouse[Value]),ALLSELECTED(WareHouse[WareHouse])) --> Gives you the total of distinct values per warehouse

If(....... =1,"",...) ---> tests for the distinct values =1, thie means they are all the same. Returns blank if that is the case, and the sum if they are different.

 

 

 

Thanks,

 

Pi

  • Thor2022's avatar
    Thor2022
    Frequent Visitor
    3 years ago

    Hi Pi

    Thanks a lot, I will try it on Monday. 

    Until then, I just need to add that the profit value is a measure, not a column .. so I am not sure if this DAX can be applied? 

    Thanks a gain 

    Regards 

    • PaulDBrown's avatar
      PaulDBrown
      Community Champion
      3 years ago

      Here is one way. Basically you compare the sum (profit) of each warehouse with the average for all warehouses in a year.

      First the model:

       The calculation (without totals)

       

      No duplicate profits =
VAR _Profit =
    SUM ( fTable[Profit] )
VAR _Average =
    CALCULATE ( AVERAGE ( fTable[Profit] ), ALL ( 'Warehouse table'[Warehouse] ) )
RETURN
    IF (
        AND (
            ISINSCOPE ( 'Warehouse table'[Warehouse] ),
            ISINSCOPE ( 'Year Table'[Year] )
        ),
        IF ( _Profit = _Average, BLANK (), _Profit )
    )

       

      and if you need totals:

       

      No Dups with totals = 
SUMX(SUMMARIZE(fTable, 'Warehouse table'[Warehouse], 'Year Table'[Year]), [No duplicate profits])

       

       

      Sample PBIX attached

      • pi_eye's avatar
        pi_eye
        Resolver IV
        3 years ago

        Hi Thor2022 

         

        This is interesting, because for some reason it's not as simple to aggregate a distinct count on another measure! However it is always possible in DAX 😉

         

        I created a new measure rather than chain it in called "New count" which evaluates to the total number of distinct sums. I am use group by to create an aggregated table which I can pass the summed column through to a  distinct count.

        New Count = calculate(
                countx(
                    distinct(SELECTCOLUMNS( GROUPBY(WareHouse,WareHouse[WareHouse],"SumVal",sumx(CURRENTGROUP(),WareHouse[Value])),[SumVal]) ) ,
                    [SumVal] ),
                ALLSELECTED(WareHouse[WareHouse])
        )
         
        On it's own, it looks like this: (sorry I can't seem to cut and paste images right now)
         12345678 
        WH142123333 
        WH242123333 
        WH342123333 
        WH442123333 
                  
         

        Added into the final expression gives you: 

        Show diff Values = If([New Count]=1,"", Sum(WareHouse[Value]))

         

        Let me know if this works,

        Pi

    • pi_eye's avatar
      pi_eye
      Resolver IV
      3 years ago

      Hi @Thor2022 

       

      This is interesting, because for some reason it's not as simple to aggregate a distinct count on another measure! However it is always possible in DAX ğŸ˜‰

       

       

      I created a new measure rather than chain it in called "New count" which evaluates to the total number of distinct sums. I am use group by to create an aggregated table which I can pass the summed column through to a  distinct count.

      New Count = calculate(
              countx(
                  distinct(SELECTCOLUMNS( GROUPBY(WareHouse,WareHouse[WareHouse],"SumVal",sumx(CURRENTGROUP(),WareHouse[Value])),[SumVal]) ) ,
                  [SumVal] ),
              ALLSELECTED(WareHouse[WareHouse])
      )
       
      On it's own, it looks like this: (sorry I can't seem to cut and paste images right now)
       12345678 
      WH142123333 
      WH242123333 
      WH342123333 
      WH442123333 
                
       

      Added into the final expression gives you: 

      Show diff Values = If([New Count]=1,"", Sum(WareHouse[Value]))

       

      Let me know if this works,

      Pi