Dynamic Average (calendar year to date)

[Anonymous]

Hi experts! 🙂

I am trying to create a dynamic average of the sales based on the current year sales (calendar year to date)
so it would be the average sales from jan'2020 until july'2020

and then when I ad August, it would add up August and calculate the new average based on the 8 months from the year
What formula should I use? I tried using Averagex, but I think I missed something.

thanks for the help

[v-alq-msft]

Hi, @Anonymous 

If you take the answer of someone, please mark it as the solution to help the other members who have same problems find it more quickly. If not, let me know and I'll try to help you further. Thanks.

Best Regards

Allan

[mhossain]

Hi @Anonymous 

Can you try this ----- YTD Avg = CALCULATE(AVERAGE(Table[Value]), DATESYTD(Table[Date], "mention the date here"))

In order to make YTD dynamic at the place of "mention the date here" you can use some time intelligence table probably.

[Anonymous]

it didnt work 😞
@mhossain 

this is my table set, I am trying to get the average of Sales from January2020 until the latest month that year.

[v-alq-msft · Accepted solution]

Hi, @Anonymous 

Based on your description, I created data to reproduce your scenario. The pbix file is attached in the end.

Table:

You may create  calculated columns and a measure as below to get the average of Sales from January2020 until the latest month(August) that year.
Calculated column:

Year = YEAR('Table'[Date])

Month = MONTH('Table'[Date])

YearMonth = YEAR('Table'[Date])*100+MONTH('Table'[Date])

Measure:

Avg = 
DIVIDE(
    CALCULATE(
        SUM('Table'[Sell Out(MSU)]),
        FILTER(
            ALL('Table'),
            [Year]=YEAR(TODAY())&&
            [Month]>=1&&
            [Month]<=MONTH(TODAY())
        )
    ),
    CALCULATE(
        DISTINCTCOUNT('Table'[YearMonth]),
        FILTER(
            ALL('Table'),
            [Year]=YEAR(TODAY())&&
            [Month]>=1&&
            [Month]<=MONTH(TODAY())
        )
    )
)

Result:

Best Regards

Allan

If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.