Forum Discussion

Anonymous's avatar
Anonymous
Not applicable
5 years ago
Solved

Distribute date ranges into groups automatically

Hello community folks!   I am trying to break project date ranges into 3 equal groups (where possible)  I have a list of all dates each project was worked, and want to automatically show which 3rd ...
Need Help
Show and Tell
Tips and Tricks
  • v-kelly-msft's avatar
    v-kelly-msft
    5 years ago

    Hi  Anonymous ，

     

    First create a column as below:

    Rank = RANKX(FILTER('Table','Table'[Project #]=EARLIER('Table'[Project #])),'Table'[Dates worked],,ASC)

    Then create a measure as below:

    Thirds = 
var _max=MAXX(FILTER(ALL('Table'),'Table'[Project #]=MAX('Table'[Project #])),'Table'[Rank])
var _count=CALCULATE(COUNT('Table'[Project #]),FILTER(ALL('Table'),'Table'[Project #]=MAX('Table'[Project #])))
Return
IF(_max<=3,MAX('Table'[Rank]),DIVIDE(MAX('Table'[Rank]),_count/3))

    And you will see:

    For the related .pbix file,pls see attached.

     

    Best Regards,
    Kelly
    Did I answer your question? Mark my post as a solution!
Anonymous's avatar
Anonymous
Not applicable
5 years ago

Anonymous  im sorry to say that did not work.

 

With a live example, this is the result of your formula 

Project #Dates worked 
Project 1Friday, June 26, 20202
Project 1Saturday, June 27, 20201
Project 1Sunday, June 28, 20201
Project 1Monday, June 29, 20201
Project 1Tuesday, June 30, 20203
Project 1Wednesday, July 1, 20201
Project 1Thursday, July 2, 20201
Project 1Friday, July 3, 20202
Project 1Saturday, July 4, 20202
Project 1Sunday, July 5, 20201
Project 1Monday, July 6, 20203
Project 1Tuesday, July 7, 20202
Project 1Wednesday, July 8, 20203
Project 1Thursday, July 9, 20201
Project 1Friday, July 10, 20202
Project 1Saturday, July 11, 20201
Project 1Sunday, July 12, 20201
Project 1Monday, July 13, 20201
Project 1Tuesday, July 14, 20203
Project 1Wednesday, July 15, 20201
Project 1Thursday, July 16, 20201
Project 1Friday, July 17, 20203
Project 1Saturday, July 18, 20201
Project 1Sunday, July 19, 20201
Project 1Monday, July 20, 20201
Project 1Tuesday, July 21, 20201
Project 1Wednesday, July 22, 20203
Project 1Thursday, July 23, 20203
Project 1Friday, July 24, 20202
Project 1Saturday, July 25, 20203
Project 1Sunday, July 26, 20203
Project 1Monday, July 27, 20203

 

the result im looking for is below

Project #Dates worked 
Project 1Friday, June 26, 20201
Project 1Saturday, June 27, 20201
Project 1Sunday, June 28, 20201
Project 1Monday, June 29, 20201
Project 1Tuesday, June 30, 20201
Project 1Wednesday, July 1, 20201
Project 1Thursday, July 2, 20201
Project 1Friday, July 3, 20201
Project 1Saturday, July 4, 20201
Project 1Sunday, July 5, 20201
Project 1Monday, July 6, 20201
Project 1Tuesday, July 7, 20202
Project 1Wednesday, July 8, 20202
Project 1Thursday, July 9, 20202
Project 1Friday, July 10, 20202
Project 1Saturday, July 11, 20202
Project 1Sunday, July 12, 20202
Project 1Monday, July 13, 20202
Project 1Tuesday, July 14, 20202
Project 1Wednesday, July 15, 20202
Project 1Thursday, July 16, 20202
Project 1Friday, July 17, 20202
Project 1Saturday, July 18, 20203
Project 1Sunday, July 19, 20203
Project 1Monday, July 20, 20203
Project 1Tuesday, July 21, 20203
Project 1Wednesday, July 22, 20203
Project 1Thursday, July 23, 20203
Project 1Friday, July 24, 20203
Project 1Saturday, July 25, 20203
Project 1Sunday, July 26, 20203
Project 1Monday, July 27, 20203

 

Im trying to break the Projects duration into 3 parts... in chronological order.   So in the case above, the first 11 dates would be "1", the middle "2", and the latter "3"

Anonymous's avatar
Anonymous
Not applicable
5 years ago

Hi Anonymous 

 

_number = 
var _cnt = rankx(allselected(Table1),CALCULATE ( MAX (Table1[Dates worked])),,ASC)
var _max = CALCULATE(COUNTROWS(Table1),ALLEXCEPT(table1,Table1[Project #]))
var _d3 = _max/3
return CEILING(_cnt/_d3,1)
  • Anonymous's avatar
    Anonymous
    Not applicable
    5 years ago

    Anonymous 

     

    So as a measure, it doesn't seem to stop at 3.  I see values up into the hundreds.

     

    because of the insight im looking to get, the best solution for this would be a calculated column..however when i add the formula in for my new column I get the error "A circular dependency was detected: Table1[Column]."

     

    any thoughts?

     

    • Anonymous's avatar
      Anonymous
      Not applicable
      5 years ago

      Hi Anonymous 

      According to your sample my previous reply answers your question.

       

      Probably you should put more time in making a good sample of your data when ask so that you get to the point reply.

       Try the below as a measure, column is preferred when there is a calculation done for each row.

       

      _number = 
var _cnt = rankx(allselected(Table1),CALCULATE ( MAX (Table1[Dates worked]), allexcept(table1, table1[Project #])),,ASC)
var _max = CALCULATE(COUNTROWS(Table1),ALLEXCEPT(table1,Table1[Project #]))
var _d3 = _max/3
return CEILING(_cnt/_d3,1)

       

       

      • Anonymous's avatar
        Anonymous
        Not applicable
        5 years ago

        My apologies that my request was unclear.  I don't use the forums often to request help, so forgive me for thinking I had explained what i was looking for thoroughly enough.

         

        I have tried your measure, and its actually gotten worse in the number return.  

         

        I shall try to explain this more in depth.

         

        The need:  To break down a Projects duration (start to finish) into thirds.  Identify which dates fall into which 3rd of each project.   Durations can be anywhere from 1 day to hundreds of days long. We have a table with thousands of projects of varying durations.  I have already created a table that shows the Project Number and each individual date the project was active.  shown here

         

        Example Table:

        Project #Dates worked
        Project 17/4/2019
        Project 17/5/2019
        Project 17/6/2019
        Project 17/7/2019
        Project 17/8/2019
        Project 17/9/2019
        Project 28/10/2019
        Project 28/11/2019
        Project 35/4/2019
        Project 35/5/2019
        Project 35/6/2019

         

         

        The request:  Can anyone help me create a Calculated Column, either in DAX or in Power Query, to label each row as either the first, middle or latter third of a project.  The result would look like below

         

        Example Table 2: Desired Outcome

        Project #Dates workedThirds
        Project 17/4/20191
        Project 17/5/20191
        Project 17/6/20192
        Project 17/7/20192
        Project 17/8/20193
        Project 17/9/20193
        Project 28/10/20191
        Project 28/11/20192
        Project 35/4/20191
        Project 35/5/20192
        Project 35/6/20193

         

         

        I hope this explanation is clearer than my original ask.