Forum Discussion
Distinct count
- 6 years ago
hi Anonymous
try
Measure90 = CALCULATE(DISTINCTCOUNT(Table1[Column1]);ALL(Table1);Table1[Date]>=(Today()-90)) Measure60 = CALCULATE(DISTINCTCOUNT(Table1[Column1]);ALL(Table1);Table1[Date]>=(Today()-60)) Measure30 = CALCULATE(DISTINCTCOUNT(Table1[Column1]);ALL(Table1);Table1[Date]>=(Today()-30))do not hesitate to give a kudo to useful posts and mark solutions as solution
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hi Anonymous
try
Measure90 = CALCULATE(DISTINCTCOUNT(Table1[Column1]);ALL(Table1);Table1[Date]>=(Today()-90))
Measure60 = CALCULATE(DISTINCTCOUNT(Table1[Column1]);ALL(Table1);Table1[Date]>=(Today()-60))
Measure30 = CALCULATE(DISTINCTCOUNT(Table1[Column1]);ALL(Table1);Table1[Date]>=(Today()-30))do not hesitate to give a kudo to useful posts and mark solutions as solution
Linkedin
- Anonymous6 years agoNot applicable
That was apt. Thanks a ton.
- Anonymous6 years agoNot applicable
az38what if i have to filter this further? for example;
Date RJC# ACP#
1/3/2019 0 1
1/3/2019 1 0
1/2/2019 0 1
1/2/2019 1 0
1/2/2019 1 0
1/1/2019 0 1
1/1/2019 1 0
1/1/2019 1 0
1/1/2019 1 0
Keeping the earlier 30, 60 90 days in filters, what we want to find out id the count of one RJC: for every date within last 30, 60 90 days, we need to count RJC# where RJC# for a given date should be less than or equal to 1.
for 1/1/2019, RJC# is 3 and 4th one is ACP# so it should be treated as 0. Where as for 1/3/2019, RJC# is 1 so it should be treated as 1.
Pls advise.