Distinct count based on value and date

[SanderAR]

Hello,

I have a question about using distinct count based on a number and date in Power Bi. 

I have 1 column with accountnumers which have duplicates, column accountnum, I also have dates on which 

transactions have been made. 

I have to create a bar chart showing active customers per year and month based on accountnumber and transaction date.

When i use distinct count I only get a total of the amount of unique accountnumber, is there any way to use distinct count combined with the date to show active clients per date? 

Example:

Accountnum:    Date

551                    01-10-2016

551                    01-11-2016

551                    01-12-2016

551                    01-01-2017

551                    01-02-2017

551                    01-03-2017

552                    01-01-2015

552                    01-03-2015

553                    01-05-2015

554                    01-01-2016

556                    01-04-2017

551 should show as active in the period 10-2016 - 03-2017 in a bar chart filterable on year and month. 

Hope someone can help out!

[TomMartens · Accepted solution]

Basically it should work.

[TomMartens]

Hey,

does this not work:

• Use the date on the x-axis (make sure that the property "Type" of the x-axis is set to categorical)
• Use the column accountnum in the value section of the visual and set the aggregation to Count (Distinct)

Hope this helps

[SanderAR]

Hi Tom,

Thanks for the fast reply and solution, it seems to work but I still only get the total amount of 5xxx and year and month 

filters don't work, should they? If so it's a relational problem, which I can solve myself. 

Thanks for the help in advance!

[v-sihou-msft · Accepted solution]

@SanderAR

If you want to calculate the active users per date, you can just create a measure to distinct count accounts group on date level.

Active Users = 
CALCULATE (
    DISTINCTCOUNT ( Table[AccountNum] ),
    ALLEXCEPT ( Table, Table[Date] )
)

Regards,

[TomMartens · Accepted solution]

Basically it should work.