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Moe_M
Regular Visitor

Distinct count based on 2 or more values of another column

Good day all, 
I have a dataset that looks like below. I was trying to get a distinct count of 'sentence_id' column when 'level_3' is both 'actions' and 'contacts'. 

sentence_idlevel_3
1280590690

Actions

1280590690

Contact

1280590690

Actions

1280590690

Actions

1280590690

Actions

1280590690

Contact

1280590690

Contact

1 ACCEPTED SOLUTION
v-tangjie-msft
Community Support
Community Support

Hi @Moe_M ,

 

According to your description, here are my steps you can follow as a solution.

(1) This is my test data.  

vtangjiemsft_0-1695366706087.png

(2) We can create a measures. 

Measure = CONCATENATEX(FILTER(ALLSELECTED('Table'),[sentence_id] in VALUES('Table'[sentence_id])),[level_3],",")
Measure 2 = var a={"Actions","Contact"}
var b=COUNTROWS(FILTER(a,CONTAINSSTRING([Measure],[Value])))
return IF(b=COUNTROWS(a),1,0)
Measure 3 = CALCULATE(DISTINCTCOUNT('Table'[sentence_id]),FILTER('Table',[Measure 2]=1))

(3) Then the result is as follows.

vtangjiemsft_1-1695368037632.png

Best Regards,

Neeko Tang

If this post  helps, then please consider Accept it as the solution  to help the other members find it more quickly. 

View solution in original post

2 REPLIES 2
v-tangjie-msft
Community Support
Community Support

Hi @Moe_M ,

 

According to your description, here are my steps you can follow as a solution.

(1) This is my test data.  

vtangjiemsft_0-1695366706087.png

(2) We can create a measures. 

Measure = CONCATENATEX(FILTER(ALLSELECTED('Table'),[sentence_id] in VALUES('Table'[sentence_id])),[level_3],",")
Measure 2 = var a={"Actions","Contact"}
var b=COUNTROWS(FILTER(a,CONTAINSSTRING([Measure],[Value])))
return IF(b=COUNTROWS(a),1,0)
Measure 3 = CALCULATE(DISTINCTCOUNT('Table'[sentence_id]),FILTER('Table',[Measure 2]=1))

(3) Then the result is as follows.

vtangjiemsft_1-1695368037632.png

Best Regards,

Neeko Tang

If this post  helps, then please consider Accept it as the solution  to help the other members find it more quickly. 

amitchandak
Super User
Super User

@Moe_M , not very clear but try like

 

countrows(summarize(Table, Table[sentence_id], Table[level_3]) ) 

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