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Anonymous's avatar
Anonymous
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5 years ago
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Distinct Count based on Most Recent Date

Hello, I am trying to find the distinct count for each party type and ID by risk. I deciced to merge the Party Type and ID columns (merged) and calculate the distinct count of this new, merged column...
  • westwrightj's avatar
    5 years ago

    Hey Anonymous ,

     

        I think I understand what you are trying to do here.

     

    Below is the sample data I am using

     

     

     

    The problem you identified makes complete sense, you are looking for distinct counts but want to assign each unique ID-Party Type combination to the most recent month

     

    So first I'll perform a similar combined column as you mentioned

     

    ID_Party Type = 
    
    'Sample Datas'[ID ]&"_"&'Sample Datas'[Party Type]

     

     

    Have gone ahead in the query editor and changed values for "Sept" to "Sep"

     

    Next we can create a makeshift date column based on what we have available

     

    Date Column = 
    
    "01/" & ('Sample Datas'[Month]) & "/" & 'Sample Datas'[Year]

     

    Then we can change the column type to "Date"

     

    Next we can 'rank' the ID_Party Type combinations by date so the most recent is always ranked first

     

    Ranked_ID Party Type = 
    
    var ID_PartyType = 'Sample Datas'[ID_Party Type]
    
    return
    
    RANKX(
    FILTER('Sample Datas', 'Sample Datas'[ID_Party Type] = ID_PartyType),
    'Sample Datas'[Date Column],
    'Sample Datas'[Date Column], DESC, Dense)

     

    Now we if use either of the below measurements if you want to count unique ID or unique Party-ID combinations

    Distinct Count of ID = 
    
    CALCULATE(DISTINCTCOUNT('Sample Datas'[ID ]), 'Sample Datas'[Ranked_ID Party Type] = 1)
    
    
    Distinct Count of Party-ID = 
    
    CALCULATE(DISTINCTCOUNT('Sample Datas'[ID_Party Type]), 'Sample Datas'[Ranked_ID Party Type] = 1)

     

     

    In this case you can use the date coulmn we made earlier for the columns.

     

     

    Let me know if this solution works for you or if we need to tinker a bit more