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Hi ,
I have a requirement where I need to calcuate "Number of projects created" for last 30 days, 30-60 days and above 60 days.
I have two date columns "actual start date" and "Expected delivery date".
Solved! Go to Solution.
Hi @shyamily_123 ,
According to your description , you mean counting the number of projects with a project time of 30 days, 30-60 days, and more than 60 days, right? Here are my steps you can follow as a solution.
(1) This is my test data.
(2) We can create calculated columns.
Column = var a=DATEDIFF('Table'[Actual start date],'Table'[Expected delivery date],DAY)
return SWITCH(TRUE(),a<30,"<30",a>=30&&a<=60,"30~60",a>60,">60")
Column 2 = COUNTAx(FILTER('Table','Table'[Column]=EARLIER('Table'[Column])),[Column])
(3) Then the result is as follows.
If the above one can't help you get the desired result, please provide some sample data in your tables (exclude sensitive data) with Text format and your expected result with backend logic and special examples. It is better if you can share a simplified pbix file. Thank you.
Best Regards,
Neeko Tang
If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.
Hi @shyamily_123 ,
According to your description , you mean counting the number of projects with a project time of 30 days, 30-60 days, and more than 60 days, right? Here are my steps you can follow as a solution.
(1) This is my test data.
(2) We can create calculated columns.
Column = var a=DATEDIFF('Table'[Actual start date],'Table'[Expected delivery date],DAY)
return SWITCH(TRUE(),a<30,"<30",a>=30&&a<=60,"30~60",a>60,">60")
Column 2 = COUNTAx(FILTER('Table','Table'[Column]=EARLIER('Table'[Column])),[Column])
(3) Then the result is as follows.
If the above one can't help you get the desired result, please provide some sample data in your tables (exclude sensitive data) with Text format and your expected result with backend logic and special examples. It is better if you can share a simplified pbix file. Thank you.
Best Regards,
Neeko Tang
If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.
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